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Top Forums Shell Programming and Scripting Help with making the output of a command a variable Post 303034613 by Defunct_Lizard on Tuesday 30th of April 2019 08:38:29 PM
Old 04-30-2019
Help with making the output of a command a variable

I'm writing a script that goes something like this:

Code:
#!/bin/bash

zenity --list --checklist --title="Choose Packages to Install" --width="1000" --height="400" \
--column="Select" --column="Package Name" --column="Description" \
GIMP=$( " " GIMP "GIMP is a free and open source photo editor."  \ )
if [ $GIMP == "GIMP" ]
then 
	sudo apt-get install $GIMP
fi

I want to open a dialog box with check boxes, package names, and descriptions. The box I have written is the first attached file.

I plan on adding other programs, but I have not gotten there yet.

The
Code:
" "

in the line
Code:
" " GIMP "Known as GIMP, GNU Image Manipulation Program is a free and open source photo editor." \

is for the first checkbox.

My main problem is the quotation marks at the end and beginning of the line (attached file #2). The quotation marks read in the wrong direction, and not how I want them to, having quotation marks inside of quotation marks?

Is there any way to fix this? Do I need to take a completely different approach?
Help with making the output of a command a variable-dialogbox10png
Help with making the output of a command a variable-zenity1png

Last edited by Defunct_Lizard; 04-30-2019 at 10:15 PM.. Reason: I did not intend for the attached files not to be alongside the text.
 

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