Write a script using a Linux shell programming language to perform clock management for a small daycare.
The program should manage all time in and out routines. At the end of the each day should give the Total hours worked that day.
Example:
Code:
Time-In 6:30am
Lunch-Out 11 :25am
Lunch-In 11:40pm
Time-Out 5:30pm
Total Hours Worked =
I have no clue where to start. I tried take in the user's input for IN/OUT Time, but then I'm not sure how to parse it to calculate the total hours. Not sure if there is another approach for this.
Moderator's Comments:
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Last edited by RavinderSingh13; 04-21-2019 at 10:37 PM..
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Hi All,
I have the following time stamp data in 2 columns
Date TimeStamp(also with milliseconds)
05/23/2012 08:30:11.250
05/23/2012 08:30:15.500
05/23/2012 08:31.15.500
.
.
etc
From this data I need the following output.
0.00( row1-row1 in seconds)
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Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
Write an awk script(company.awk) for the workers file to find the number of workers of each departman, total... (8 Replies)
Hello Friends,
I've been trying to calculate total number of a certain match in multiple data records files (DRs).
Let say I have a daily created folders for each day since the beginning of july like the following
drwxrwxrwx 2 mmsuper med 65536 Jul 1 23:59 20150701
drwxrwxrwx 2 mmsuper... (1 Reply)
Discussion started by: EAGL€
1 Replies
LEARN ABOUT DEBIAN
time::julianday
Time::JulianDay(3pm) User Contributed Perl Documentation Time::JulianDay(3pm)NAME
Time::JulianDay -- Julian calendar manipulations
SYNOPSIS
use Time::JulianDay
$jd = julian_day($year, $month_1_to_12, $day)
$jd = local_julian_day($seconds_since_1970);
$jd = gm_julian_day($seconds_since_1970);
($year, $month_1_to_12, $day) = inverse_julian_day($jd)
$dow = day_of_week($jd)
print (Sun,Mon,Tue,Wed,Thu,Fri,Sat)[$dow];
$seconds_since_jan_1_1970 = jd_secondslocal($jd, $hour, $min, $sec)
$seconds_since_jan_1_1970 = jd_secondsgm($jd, $hour, $min, $sec)
$seconds_since_jan_1_1970 = jd_timelocal($sec,$min,$hours,$mday,$month_0_to_11,$year)
$seconds_since_jan_1_1970 = jd_timegm($sec,$min,$hours,$mday,$month_0_to_11,$year)
DESCRIPTION
JulianDay is a package that manipulates dates as number of days since some time a long time ago. It's easy to add and subtract time using
julian days...
The day_of_week returned by day_of_week() is 0 for Sunday, and 6 for Saturday and everything else is in between.
ERRATA
Time::JulianDay is not a correct implementation. There are two problems. The first problem is that Time::JulianDay only works with
integers. Julian Day can be fractional to represent time within a day. If you call inverse_julian_day() with a non-integer time, it will
often give you an incorrect result.
The second problem is that Julian Days start at noon rather than midnight. The julian_day() function returns results that are too large by
0.5.
What to do about these problems is currently open for debate. I'm tempted to leave the current functions alone and add a second set with
more accurate behavior.
There is another implementation in Astro::Time that may be more accurate.
GENESIS
Written by David Muir Sharnoff <cpan@dave.sharnoff.org> with help from previous work by Kurt Jaeger aka PI
<zrzr0111@helpdesk.rus.uni-stuttgart.de>
based on postings from: Ian Miller <ian_m@cix.compulink.co.uk>; Gary Puckering <garyp%cognos.uucp@uunet.uu.net> based on
Collected Algorithms of the ACM ?; and the unknown-to-me author of Time::Local.
LICENSE
Copyright (C) 1996-1999 David Muir Sharnoff. License hereby granted for anyone to use, modify or redistribute this module at their own
risk. Please feed useful changes back to cpan@dave.sharnoff.org.
perl v5.12.3 2011-05-06 Time::JulianDay(3pm)
04-21-2019
