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Full Discussion: Countdown timer with seconds
Operating Systems Linux Ubuntu Countdown timer with seconds Post 303033496 by drew77 on Saturday 6th of April 2019 03:35:24 PM
Old 04-06-2019
Code:
#!/bin/bash
# 
 
if [ "$#" -lt "2" ] ; then 
    echo "Incorrect usage ! Example:" 
    echo './CountDown.sh -d  "Jun 10 2011 16:06"' 
    echo 'or' 
    echo './CountDown.sh -m  90' 
    echo 'or'
    echo './CoundDown.sh -s 5'
    exit 1 
fi 
 
now=`date +%s` 
 
if [ "$1" = "-d" ] ; then 
    until=`date -d "$2" +%s` 
    sec_rem=`expr $until - $now` 
    echo "-d" 
    if [ $sec_rem -lt 1 ]; then 
        echo "$2 is already history !" 
    fi 
fi 
 
if [ "$1" = "-m" ] ; then 
    until=`expr 60 \* $2` 
    until=`expr $until + $now` 
    sec_rem=`expr $until - $now` 
    echo "-m" 
    if [ $sec_rem -lt 1 ]; then 
        echo "$2 is already history !" 
    fi
if [ "$1" = "-s" ] ; then 
    until=`expr \* $2` 
    until=`expr $until + $now` 
    sec_rem=`expr $until - $now` 
    echo "-s" 
    if [ $sec_rem -lt 1 ]; then 
        echo "$2 is already history !" 
    fi     
     
fi 
 
_R=0
_C=7
tmp=0
percent=0
total_time=0
col=`tput cols`
col=$[ $col -5 ]

while [ $sec_rem -gt 0 ]; do 
    clear 
    date 
    let sec_rem=$sec_rem-1 
    interval=$sec_rem 
    seconds=`expr $interval % 60` 
    interval=`expr $interval - $seconds` 
    minutes=`expr $interval % 3600 / 60` 
    interval=`expr $interval - $minutes` 
    hours=`expr $interval % 86400 / 3600` 
    interval=`expr $interval - $hours` 
    days=`expr $interval % 604800 / 86400` 
    interval=`expr $interval - $hours` 
    weeks=`expr $interval / 604800` 
    echo "----------------------------" 
    echo "Seconds: " $seconds 
    echo "Minutes: " $minutes 
    echo "Hours:   " $hours 
    echo "Days:    " $days 
    echo "Weeks:   " $weeks 

    echo -n "["

    progress=$[$progress + 1]
    if [ $total_time -lt 1 ] ; then
        total_time=$[$hours * 3600 + $minutes * 60 + $seconds]
    fi
    
    printf -v f "%$(echo $_R)s>" ; printf "%s\n" "${f// /=}"
    _C=7
    tput cup 7 $col

    tmp=$percent
    percent=$[$progress * 100 / $total_time]
    printf "]%d%%" $percent
    change=$[$percent - $tmp]

    _R=$[ $col * $percent / 100 ]

    sleep 1
done
printf "\n"

Code:
test.sh -s 9
 /home/andy/bin/test.sh: line 95: syntax error: unexpected end of file



Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!

Last edited by RudiC; 04-06-2019 at 04:44 PM.. Reason: Added CODE tags.
 

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