Because argv[0] actually exists, even in a program with no arguments - it's the name of the calling program. Again, why should it segfault? What exact fault should it be catching here? Segmentation fault means "touched memory I don't have permission to use", and if you don't do that, you don't get a segfault, even if you leap around like a flea on a hot griddle.
IMO gcc should check for any assembly jumps outside the bounds of any individual function, irrespective of how one compiles it. Just because the first code uses two near identical functions is irrelevant the 'asm()' function is taking functions out of their boundaries.
And, I don't intend, ever, to use this bad coding method at all. It was an exercise in finding out as I was researching about 'goto' inside a function.
--- Post updated at 03:56 PM ---
Quote:
Originally Posted by jim mcnamara
How do you compile ? Try gcc -Wall -ansi mycode.c -o mycode
I'm guessing, completely. You have to read your manpage for gcc, look for the options for your hardware e.g., SPARC
Compile with the strictest settings you can find. This will eliminate some of the problems you see: gcc compiling stuff that should fail.
Try to use -std=c99 if your compiler supports it, for example. Since you run on OSX and Amiga (I think), I have to punt on what the exact command should be.
PS: a good clean compile means zero warnings/errors
Hi Jim...
Absolutely.
However I shouldn't have to type all that just to find out, gcc filename.c should be sufficient.
It should have been __asm__ volatile() but I used the generic 'asm()' as it seems 'universal' even on my AMIGA C compilers.
Thanks for your help...
EDIT:
I didn't add this as an edit, it did so itself.
Last edited by wisecracker; 03-28-2019 at 01:00 PM..
Reason: See EDIT:
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