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Top Forums Shell Programming and Scripting Remove all matches containing a string until its next space Post 303032917 by bakunin on Tuesday 26th of March 2019 03:31:40 PM
Old 03-26-2019
Quote:
Originally Posted by Tribe
I want to delete all matches in a text following this pattern:
  • Each match starts with linux-
  • Each match ends with a space
  • (Remove linux-* until immediate next space)
Are you aware that these stipulations will exclude a "linux-something" at the lines end from being removed because there will be no space afterwards? Maybe this is not what you want. Also notice that your clause 2 means that the space immediately following the word "linux-*" will be removed too.

If your goal is indeed to remove the last match too i'd suggest:

Code:
sed 's/linux-[^ ]* \{0,1\}//g' /path/to/file

If you want to retain the blank following the word but would not want to add a space at the end of the string then this:

Code:
sed 's/linux-[^ ]*\( \{0,1\}\)/\1/g' /path/to/file


I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
 

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UUID_COMPARE(3) 						    Libuuid API 						   UUID_COMPARE(3)

NAME
uuid_compare - compare whether two UUIDs are the same SYNOPSIS
#include <uuid/uuid.h> int uuid_compare(uuid_t uu1, uuid_t uu2) DESCRIPTION
The uuid_compare function compares the two supplied uuid variables uu1 and uu2 to each other. RETURN VALUE
Returns an integer less than, equal to, or greater than zero if uu1 is found, respectively, to be lexigraphically less than, equal, or greater than uu2. AUTHOR
Theodore Y. Ts'o AVAILABILITY
libuuid is part of the util-linux-ng package since version 2.15.1 and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux- ng/. SEE ALSO
uuid(3), uuid_clear(3), uuid_copy(3), uuid_generate(3), uuid_is_null(3), uuid_parse(3), uuid_unparse(3) util-linux-ng May 2009 UUID_COMPARE(3)
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