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Full Discussion: How to remove /*...*/ ?
Top Forums UNIX for Beginners Questions & Answers How to remove /*...*/ ? Post 303032531 by bakunin on Tuesday 19th of March 2019 07:12:17 PM
Old 03-19-2019
Quote:
Originally Posted by MadeInGermany
This is a case for a mimimum match.
You are right: non-greedy matching takes care of a few cases. Still, what i said about regexps being unable to parse still stands. For instance, your perl-program would have problems with:

Code:
char foo[3]="/*"; char bar[3]="*/"; /* comment */

I admit, this (and some more cases i could cite) are fringe. Maybe the thread-O/P will never encounter any of these. But again, it is - in a strict sense - impossible to overcome all of these problems (some of them, yes, but not all) because a regexp engine cannot work as a parser.

I hope this helps.

bakunin
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libtalloc_stealing(3)						      talloc						     libtalloc_stealing(3)

NAME
libtalloc_stealing - Chapter 2: Stealing a context Stealing a context Talloc has the ability to change the parent of a talloc context to another one. This operation is commonly referred to as stealing and it is one of the most important actions performed with talloc contexts. Stealing a context is necessary if we want the pointer to outlive the context it is created on. This has many possible use cases, for instance stealing a result of a database search to an in-memory cache context, changing the parent of a field of a generic structure to a more specific one or vice-versa. The most common scenario, at least in Samba, is to steal output data from a function-specific context to the output context given as an argument of that function. struct foo { char *a1; char *a2; char *a3; }; struct bar { char *wurst; struct foo *foo; }; struct foo *foo = talloc_zero(ctx, struct foo); foo->a1 = talloc_strdup(foo, "a1"); foo->a2 = talloc_strdup(foo, "a2"); foo->a3 = talloc_strdup(foo, "a3"); struct bar *bar = talloc_zero(NULL, struct bar); /* change parent of foo from ctx to bar */ bar->foo = talloc_steal(bar, foo); /* or do the same but assign foo = NULL */ bar->foo = talloc_move(bar, &foo); The talloc_move() function is similar to the talloc_steal() function but additionally sets the source pointer to NULL. In general, the source pointer itself is not changed (it only replaces the parent in the meta data). But the common usage is that the result is assigned to another variable, thus further accessing the pointer from the original variable should be avoided unless it is necessary. In this case talloc_move() is the preferred way of stealing a context. Additionally sets the source pointer to NULL, thus.protects the pointer from being accidentally freed and accessed using the old variable after its parent has been changed. Version 2.0 Tue Jun 17 2014 libtalloc_stealing(3)
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