C. To segmentation fault or not to segmentation fault, that is the question. Post: 303032348

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Top Forums Programming C. To segmentation fault or not to segmentation fault, that is the question. Post 303032348 by wisecracker on Friday 15th of March 2019 12:14:06 PM

03-15-2019

Registered User

C. To segmentation fault or not to segmentation fault, that is the question.

Oddities with gcc, 2.95.3 for the AMIGA and 4.2.1 for MY current OSX 10.14.1...

I am creating a basic calculator for the AMIGA ADE *NIX emulator in C as it does not have one.

Below are two very condensed snippets of which I have added the results inside the each code section.

IMPORTANT! This will NOT even compile on gcc 2.95.3 for the AMIGA, but WORKS correctly on OSX 10.14.1, gcc 4.2.1.

Code:

/* No_error gcc 4.2.1 demo. */

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int NUM_1;
int NUM_2;
char CHARACTER;

int main(int argc, char *argv[])
{
    /* Conditional BEFORE _variables_! */
    if (argc <= 3)
    {
        printf("ERROR!\n\n");
        printf("Not enough arguments!\n");
        exit(1);
    }

    int NUM_1 = strtod(argv[1], NULL);
    int NUM_2 = strtod(argv[3], NULL);
    CHARACTER = *argv[2];

    printf("\n%i, %i, %c\n\n", NUM_1, NUM_2, CHARACTER);

    return(0);
}


/* ****************************************
     Results OSX 10.14.1, gcc 4.2.1...

Last login: Fri Mar 15 14:45:03 on ttys000
AMIGA:amiga~> cd Desktop/Code/C
AMIGA:amiga~/Desktop/Code/C> gcc noerror.c
AMIGA:amiga~/Desktop/Code/C> ./a.out
ERROR!

Not enough arguments!
AMIGA:amiga~/Desktop/Code/C> ./a.out 1 v
ERROR!

Not enough arguments!
AMIGA:amiga~/Desktop/Code/C> ./a.out 1 v 3

1, 3, v

AMIGA:amiga~/Desktop/Code/C> _

**************************************** */

ALSO IMPORTANT! This compiles and WORKS perfectly on the AMIGA but gives a segmentation fault on OSX 10.14.1, gcc 4.2.1.

Code:

/* Error gcc 4.2.1 demo. */

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int NUM_1;
int NUM_2;
char CHARACTER;

int main(int argc, char *argv[])
{
    int NUM_1 = strtod(argv[1], NULL);
    int NUM_2 = strtod(argv[3], NULL);
    CHARACTER = *argv[2];

    /* Conditional AFTER _variables_! */
    if (argc <= 3)
    {
        printf("ERROR!\n\n");
        printf("Not enough arguments!\n");
        exit(1);
    }

    printf("\n%i, %i, %c\n\n", NUM_1, NUM_2, CHARACTER);

    return(0);
}

/* ****************************************

Last login: Fri Mar 15 15:48:37 on ttys000
AMIGA:amiga~> cd Desktop/Code/C
AMIGA:amiga~/Desktop/Code/C> gcc error.c
AMIGA:amiga~/Desktop/Code/C> ./a.out
Segmentation fault: 11
AMIGA:amiga~/Desktop/Code/C> ./a.out 1 r
Segmentation fault: 11
AMIGA:amiga~/Desktop/Code/C> ./a.out 1 r 6

1, 6, r

AMIGA:amiga~/Desktop/Code/C> _

**************************************** */

As you can see the second code gives a Segmentation fault: 11 on OSX 10.14.1, gcc 4.2.1 but compiles and works correctly on the AMIGA.

Can anyone explain why there is a SEGMENTATION FAULT when the if conditional statement is inside the 'main()' function to start with and the assignments set?

wisecracker

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