03-06-2019
Thank you RudiC & Don! I have learned a lot today. It works
9 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
HI guys,
I have created a script to read 1 column in a csv file and then place it in text file.
However, when i checked out the text file, it is not in a column format...
Example:
CSV file contains
name,age
aa,11
bb,22
cc,33
After using awk to get first column
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2. UNIX for Dummies Questions & Answers
I have an assignment in a Linux class I am taking. It has multiple scripts. Basicly when it runs it asks the user name and shows information about the user from the /etc/passwd and /etc/shadow files. The one I need help with is the one that reads the /etc/shadow file. I need to format the date into... (1 Reply)
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3. Shell Programming and Scripting
The date format in the delimited file for one column '6/27/2011 12:00:00 AM' Is it possible o change it to '2011-06-27 12:00:00 AM' for all the records..
Thanks in advance..... (8 Replies)
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4. Shell Programming and Scripting
I have this code to compare columns 1 and 10 between file1 and file 2 and give me all records that match column 1 but dont match column 10
However column 10 is date format mm/dd/yy and awk cant read it and compare ...i tried
awk < file1 -F~ '{print $10}'
and it gave blank screen
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Discussion started by: sigh2010
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5. Shell Programming and Scripting
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
Discussion started by: vegasluxor
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6. Shell Programming and Scripting
Could you tell me how to convert the following dates?
If I have m/d/yyyy, I want to have
0m/0d/yyyy. I want my dates to always be 8 digits.
In other words, I want a 0 inserted whenever the month or day is a single digit.
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7. Shell Programming and Scripting
Hi All,
I have file like
“April 10, 2013”,”raj”
“April 29, 2013”,”raj1”
Output :
“2013/04/10”,”raj”
“2013/04/29”,”raj1”
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Discussion started by: bmk
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8. Shell Programming and Scripting
Hi,
i have a flat file namely temp.txt with this data below
ID|name|contact_date
101|Kay|2013-12-26
102|let|2013-12-26
I need to modify the date data in the flat file into MM/DD/YYYY HH24:MI:SS format
let me know the code for this.
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9. Shell Programming and Scripting
Hi have a large spreadsheet which has 4 columns
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96034 Storage Mgmt Team
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LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)
cal_from_jd - Converts from Julian Day Count to a supported calendar
SYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION
cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO
cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)