for example, "echo" and "eval" commands. Both commands take parameters and do the same work. Only the first returns a string of them to the stdout and the second command to the stdin (shell stdin).
Sorry, but this is based on a misconception of what eval does. eval has no output at all, not even to the input of the current shell.
When the shell reads an input line (that might be a commandline entered by the user or a line of code from a script being executed) it starts to interpret (or "decode") this line in a process of several fixed stages. One of these steps is - for example - the replacement of wildcard-expressions by a list of filenames fitting that wildcard-expression, another step is the replacement of variable names by their respective content.
The process goes like this: you enter i.e.
and let us say there are three files which filenames start with "file". So the shell, when doing the respective stage, replaces the wildcard with the respective filelist:
Note that nothing is exeuted yet, the shell was just "cooking" the command line. Only now the result of this "cooking" is presented to the ls command. For ls there is no noticeable difference between these two forms of commands. For the same reason this is a scripting error:
Because the command (here the test-command or its equivalent [) will never see "file*" but only the list the shell creates from that and obviously in
after the workable "-r fileA" (is fileA readable?) there are two filenames test simply doesn't know what to do with.
Now, after this, what does eval do? It restarts the process of evaluating the command line so that the already done stages are done a second time. Where would one need that? For instance, when replacing variables with their content you can do:
but you cannot do:
because all variables are replaced at the same time and you would need to first replace "$x" with "1" and only then replace the resulting "$var1" with "one". You can do this with eval, though, because this way you get two stages of "variable replacement" and you can (with the help of escaping) put them in the necessary order:
The shell will do the following: the first "\$var" will not be expanded, because the escaped "$" will make it a ordinary character and hence "$var" is simply a string, not a variable. The "$x" is expanded, though, and replaced by a "1":
Now the "eval" makes the shell interpret it again and in the next variable replacement stage it will recognise the "$var1" as a now legal variable name and this time expand it:
I hope this helps.
bakunin
These 2 Users Gave Thanks to bakunin For This Post:
My script has the following for loop in it.
foreach id (CLKM4 DGTM4 GNNM4)
eval echo $id \$${id}sf \$${id}sfk
end
so "id" is a variable defined in the loop, and "idsf" and "idsfk" are variables defined in another part of the script, they return values of 0 or more. The problem i'm... (2 Replies)
Hi All,
I'm running some encrypted data through a script I wrote. In order to do this, I'm using eval to resolve some of my variables. At the moment, when I use eval to resolve, it strips out some of my encrypted values, and totally drops some others. For example if I have the value ab1"3 it drops... (1 Reply)
Bit of a weird one i suppose, i want to use an echo inside an echo... For example...
i have a script that i want to use to take users input and create another script. Inside this script it creates it also needs to use echos...
echo "echo "hello"" >$file
echo "echo "goodbye"" >$file
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So, I'm looking over /proc/cpuinfo and have a question... I've read that "siblings" refers to hyperthreading, but that seems odd considering the contents of cpuinfo. Here's a part:
model name : Intel(R) Xeon(R) CPU E5410 @ 2.33GHz
physical id : 0
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Hi:
how come this command does not work? the error message is:
xargs: cd: No such file or directory
yet, in the same time, 'echo dir_path | xargs ls' works.
Does it work in bash? We use csh.
Thanks.
NB Phil (7 Replies)
my command deletes the oldest file from a folder and I'd like to have some type of output when the file is selected or deleted.
ls -t -1 | tail -n 1 | xargs rm
I'm not sure how to incorporate echo into this.
Thanks, (2 Replies)
Hi all,
some small script with eval turned me to crazy.
my OS is linux
Linux s10-1310 2.6.16.53-0.8.PTF.434477.3.TDC.0-smp #1 SMP Fri Aug 31 06:07:27 PDT 2007 x86_64 x86_64 x86_64 GNU/Linux
below script works well
#!/bin/bash
eval ssh remotehost date
eval ssh remotehost ls
below... (1 Reply)