For i in loops on 2 arrays Post: 303031365

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Top Forums Shell Programming and Scripting For i in loops on 2 arrays Post 303031365 by Don Cragun on Wednesday 27th of February 2019 06:11:21 AM

02-27-2019

Registered User

It would seem to be because you have nested loops instead of having sequential loops. And, break with no operand only breaks out of the nearest enclosing loop. To break out of two nested loops you would need to use break 2.

Furthermore, the code you have (with nested loops) isn't testing A, B, C, one, two, three; it is testing A, B, C, one, A, B, C, two, A, B, C, three which doesn't seem necessary.

But, even if you fix that, I'm not sure why you're creating arrays and using loops. It looks like a simple case statement would be a better approach:

Code:

VAR=${1:-B}
case "$VAR" in
	(*A*|*B*|*C*)
		VAR=LETTERS;;
	(*one*|*two*|*three*)
		VAR=NUMBERS;;
	(*)	VAR=DEFAULT
esac
echo "$VAR"

If you insist on doing it with loops and arrays you would need to make the loops sequential instead of nested:

Code:

VAR=${1:-B}
found=0

ARRAY_1=(one two three)
ARRAY_2=(A B C)

for LETTERS in "${ARRAY_2[@]}"
do	if [[ $VAR == *"$LETTERS"* ]]
	then	VAR=LETTERS
		found=1
		break
        fi
done
if [[ $found == 0 ]]
then	for NUMBERS in "${ARRAY_1[@]}"
	do	if [[ $VAR == *"$LETTERS"* ]]
		then	VAR=NUMBERS
			found=1
			break
		fi
	done
fi
if [[ $found == 0 ]]
then	VAR=DEFAULT
fi

echo "$VAR"

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