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Top Forums UNIX for Beginners Questions & Answers Remove lines ending with a certain character Post 303031151 by RudiC on Friday 22nd of February 2019 07:18:27 AM
Old 02-22-2019
Welcome to the forum.


You weren't too far off. Why didn't you apply what you had in your grep approach to the sed command, i.e. anchor the regex at line end? Like
Code:
sed '/0$/d' file

Or, add grep's (man grep)
Quote:
-v, --invert-match
Invert the sense of matching, to select non-matching lines.
option ?


How come your grep "gives me as output only the last line." ?
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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