Hi Friends,
i have to write a script to raise a flag if there are any files that are older than 15 minutes in the directory.The directory is supplied as the parameter to the script.
please help with a sample script.
Thanks in advance
veera (0 Replies)
I'm using k-shell in unix and I want to create a file with the current system time - 60 minutes. I know I can use touch to create the file, but I'm having trouble specifying how tell it to use the current time less 60 minutes. Any ideas??? (4 Replies)
I am looking for a way to show files that have been created within a certain period (say anything older than 10 minutes or so). Is there a command/series of commands I can do this with? As an example, I have the following in a directory:
-rw-r--r-- 1 owner group 70175 May 16 09:10... (1 Reply)
I think I can do this myself now, but I am always amazed by how people can do things cleaner and simpler than I end up doing...
Using cron, I want to save the image found at:
http://radar.weather.gov/ridge/Conus/RadarImg/centgrtlakes.gif
every 15 minutes to a local file , such as
... (1 Reply)
Hi,
I have to find the files older than 10 minutes and remove those files as well as redirect the file names into a log file.
i am using sun OS and my unix is not GNU and also not having perl.
Could any one suggest me the way to approach. It would be great if script is provided.
Also... (8 Replies)
Hi ,
I need help in getting how many minutes ago the last file, matching some pattern in file name, was created in a folder.
Thanks in advance. (8 Replies)
I wanted to send an email to the client whenever there is failed record created in a /feed/HR-76/failed folder after processing of feed file.
I can find out with the help of below script that what is the new file created but that file didn't make just 15 minutes before.
... (1 Reply)
Hi, please help with below time conversion to minutes.
one column values:
2 minutes 16 seconds 420 msec
43 seconds 750 msec
0 days 3 hours 29 minutes 58 seconds 480 msec
11 seconds 150 msec
I need output in minutes(total elapsed time in minutes) (2 Replies)
Hi all,
System Ubuntu 16.04.3 LTS
i have the following log
INFO 2019-02-07 15:13:31,099 module.py:700] default: "POST /join/8550614e-3e94-4fa5-9ab2-135eefa69c1b HTTP/1.0" 500 2042
INFO 2019-02-07 15:13:31,569 module.py:700] default: "POST /join/6cb9c452-dcb1-45f3-bcca-e33f5d450105... (15 Replies)
A process xyz is running and creating file1, file2, file3, .... filen. how do i know if the process has stopped and createtime of the last file (filen) is older than 5 minutes?
OS is AIX (3 Replies)
Discussion started by: malaika
3 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)