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Full Discussion: awk !seen[$]++ in else loop
Top Forums UNIX for Beginners Questions & Answers awk !seen[$]++ in else loop Post 303030954 by RavinderSingh13 on Tuesday 19th of February 2019 07:04:09 PM
Old 02-19-2019
Quote:
Originally Posted by ksenia
Amazing, it is doing exactly what I was searching for.
Thanks a lot!
--- Post updated at 04:21 PM ---
Can you please give walk through for "(!seen[$12]++ || ! length($12))"?
Thanks
Moderator's Comments:
Mod Comment MOD's comment: Please wrap your samples, codes into [CODE]....[/CODE] tags in all your posts as per forum's rules.
Hello ksenia,

Could you please go through following and let me know if this helps you.
This is only for understanding purposes, I haven't run it to see if this is working with comments or not(fair warning here).

Code:
sort -u -k 5,5 input_file |                         ##Using sort command on Input_file and sending its standard output as an Input to awk command, read about |(pipe) more in man bash too.
awk -F "\t" '                                       ##Starting awk program here whose input is output of sort command passed to it. Setting -F(field seprator) as TAB here for all lines of Input_file.
(!seen[$12]++ || ! length($12)) && /IPR013087/      ##Checking 2 conditions here. 1st- Either 12th field is coming first time in array named seen OR length of 12th field is ZERO.
'                                                   ##2nd condition is line should have string IPR013087 in it if BOTH conditions are TRUE then print that line.
                                                    ##Since awk works on method of condition then action and we haven't mentioned any action here so when condition is TRUE by default print of current line will happen.

Thanks,
R. Singh
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