I have a task where I need to code a shell script to extract a 10 min range (10 min from now until now) extract of a log file.
I taught I could simply use a command that would say something like Start=date - 10 min but I didn't find anything. Looks like the only solution would have to code a... (3 Replies)
All I want is to look for the pattern in the file...If I found it at # places... I want print lines after those pattern(line) until I find a blank line.
Log EXAMPLE :
MT:Exception caught
The following Numbers were affected:
1234
2345
2346
Error
java.lang.InternalError:... (3 Replies)
hey guys,
I tried searching but most 'search and replace' questions are related to one liners.
Say I have a file to be replaced that has the following:
$ cat testing.txt
TESTING
AAA
BBB
CCC
DDD
EEE
FFF
GGG
HHH
ENDTESTING
This is the input file: (3 Replies)
A log files has lines (1 line per each log for a majority; a few for 2 lines per each log)
May 31 14:00:11 rtprodapp1 local2:notice sudo: jdoe : TTY=pts/0 ; PWD=/home/jdoe ; USER=root ; COMMAND=/usr/bin/su -
May 31 14:03:19 rtprodapp1 local2:notice sudo: jdoe : TTY=pts/0 ; PWD=/home/jdoe ;... (4 Replies)
i want to search a log for a string. when that string is found, i want to grab the a set number of lines that came before the string, and a set number of lines that come after the string.
so if i search for the word "Error" in the /var/log/messages file, how can I output the 20 lines that came... (4 Replies)
I have a "main" file which has blocks of data for each user defined by tags BEGIN and END.
BEGIN
ID_NUM:24879
USER:abc123
HOW:47M
CMD1:xyz1
CMD2:arp2
STATE:active
PROCESS:id60
END
BEGIN
ID_NUM:24880
USER:def123
HOW:4M
CMD1:xyz1
CMD2:xyz2
STATE:running
PROCESS:id64
END (7 Replies)
I need to use awk for this task !
input (fields are separated by ";"):
1%2%3%4%;AA
5%6%7%8%9;AA
1%2%3%4%5%6;BB
7%8%9%10%11%12;BBIn the 1st field there are patterns composed of numbers separated by "%".
The 2nd field define groups (here two different groups called "AA" and "BB").
Records... (8 Replies)
I have a file with two ID columns followed by five columns of counts in fraction form. I'd like to print lines that have a count of at least 4 (so at least 4 in the numerator, e.g. 4/17) in at least one of the five columns.
Input file:
comp51820_c1_seq1 693 0/29 0/50 0/69 0/36 0/31... (6 Replies)
Need Assistance in shell programming... I have a huge file which has multiple stations and i wanted to search particular station and extract few lines from it and the rest is not needed
Bold letters are the stations . The whole file has multiple stations .
Below example i wanted to search... (4 Replies)
Discussion started by: ajayram_arya
4 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)