Extract lines if string found from last 30 min only
Hi guys,
Appreciate your help as I am stuck with searching the logs for last 30 minutes from the current time. Current time is time when you execute the script and it will search for <string> through the logs for last 30 minutes only and if <string> found then print those lines only.
The logfile has 2 different dates as shown below but searching should limit to the lines which are
(1) Scanning should started with syntax <Feb 12,----date----PM UTC> as shown below and
(2) Scanning should avoid the scanning of lines (2019-02-12T12:26:59.842+0000: 45.152
I tried various awk and sed option but unable to scan the logs for last 30min. Using grep <string>, it does the scanning for <string>, pull all lines even from previous day as per string pattern match but I want to restrict the search string and print logs for last 30 min only if the strings match exist else no data to be returned.
I have a task where I need to code a shell script to extract a 10 min range (10 min from now until now) extract of a log file.
I taught I could simply use a command that would say something like Start=date - 10 min but I didn't find anything. Looks like the only solution would have to code a... (3 Replies)
All I want is to look for the pattern in the file...If I found it at # places... I want print lines after those pattern(line) until I find a blank line.
Log EXAMPLE :
MT:Exception caught
The following Numbers were affected:
1234
2345
2346
Error
java.lang.InternalError:... (3 Replies)
hey guys,
I tried searching but most 'search and replace' questions are related to one liners.
Say I have a file to be replaced that has the following:
$ cat testing.txt
TESTING
AAA
BBB
CCC
DDD
EEE
FFF
GGG
HHH
ENDTESTING
This is the input file: (3 Replies)
A log files has lines (1 line per each log for a majority; a few for 2 lines per each log)
May 31 14:00:11 rtprodapp1 local2:notice sudo: jdoe : TTY=pts/0 ; PWD=/home/jdoe ; USER=root ; COMMAND=/usr/bin/su -
May 31 14:03:19 rtprodapp1 local2:notice sudo: jdoe : TTY=pts/0 ; PWD=/home/jdoe ;... (4 Replies)
i want to search a log for a string. when that string is found, i want to grab the a set number of lines that came before the string, and a set number of lines that come after the string.
so if i search for the word "Error" in the /var/log/messages file, how can I output the 20 lines that came... (4 Replies)
I have a "main" file which has blocks of data for each user defined by tags BEGIN and END.
BEGIN
ID_NUM:24879
USER:abc123
HOW:47M
CMD1:xyz1
CMD2:arp2
STATE:active
PROCESS:id60
END
BEGIN
ID_NUM:24880
USER:def123
HOW:4M
CMD1:xyz1
CMD2:xyz2
STATE:running
PROCESS:id64
END (7 Replies)
I need to use awk for this task !
input (fields are separated by ";"):
1%2%3%4%;AA
5%6%7%8%9;AA
1%2%3%4%5%6;BB
7%8%9%10%11%12;BBIn the 1st field there are patterns composed of numbers separated by "%".
The 2nd field define groups (here two different groups called "AA" and "BB").
Records... (8 Replies)
I have a file with two ID columns followed by five columns of counts in fraction form. I'd like to print lines that have a count of at least 4 (so at least 4 in the numerator, e.g. 4/17) in at least one of the five columns.
Input file:
comp51820_c1_seq1 693 0/29 0/50 0/69 0/36 0/31... (6 Replies)
Need Assistance in shell programming... I have a huge file which has multiple stations and i wanted to search particular station and extract few lines from it and the rest is not needed
Bold letters are the stations . The whole file has multiple stations .
Below example i wanted to search... (4 Replies)
Discussion started by: ajayram_arya
4 Replies
LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS -e-e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)
02-12-2019
