Thanks so much Scrutinizer. It looked like it was printing out some manner of counter (possibly string length?) as the first field of every line. I adjusted your code slightly and also for simplicity sake took out the leading space in the input file. I also needed to transcribe your code to a one-liner as I was passing output into it via pipe (I presented it as a file above for simplicity sake).
Thus, your code transcribed awk -F '[][]' '{for(i=2; i<=NF; i+=2) if($i~/<Ob>/){split($i,F," "); print i,$1 F[1]; next}}'gave me this:
I adjusted to awk -F '[][]' '{for(i=2; i<=NF; i+=2) if($i~/<Ob>/){split($i,F," "); print $1 F[1]; next}}' and while I haven't investigated in detail, that seems to have done the trick. Thanks so much!
--- Post updated at 09:18 PM ---
Quote:
Originally Posted by Don Cragun
In your sample data, the [string <0b>] always appears at the end of the line that starts with <space>s immediately followed by PS. Is that also true in your real data? If it is, we can simplify the code Scrutinizer suggested to something like:
or:
Unfortunately no Don, the string with <Ob> can appear anywhere in the line. Nevertheless, I did a bit of an adjustment to Scrutinizer's code and it seems to be working very well. Thank you so much Don.
I'm at wits end with this issue and my troubleshooting leads me to believe it is a problem with the file formatting of the array referenced by my script:
awk -F, '{if (NR==FNR) {a=$4","$3","$2}\
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On the WBTSassignments1.txt file... (2 Replies)
Hello, I am using awk to match text in a tab separated field and am able to do so when matching the exact word. My problem is that I would like to match any sequence of text in the tab-separated field without having to match it all. Any help will be appreciated. Please see the code below.
awk... (3 Replies)
i have a file like this
< '393200103052';'H3G';'20081204'
< '393200103059';'TIM';'20110111'
< '393200103061';'TIM';'20060206'
< '393200103064';'OPI';'20110623'
> '393200103052';'HKG';'20081204'
> '393200103056';'TIM';'20110111'
> '393200103088';'TIM';'20060206'
Now i have to generate a file... (9 Replies)
attempting the hangman program. This was an optional assignment from the professor. I have completed the logical coding, debugging now.
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Hi All,
I got stuck up with shell script where i use awk. The scenario which i am working on is as below.
I have a file text.txt with contents
COL1 COL2 COL3 COL4
1 A 500 400
1 B 500 400
1 A 500 200
2 A 290 300
2 B 290 280
3 C 100 100
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here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Hi
Input:
{ committed = 782958592; init = 805306368; max = 1051394048; used = 63456712; }
Result:
A map (maybe Associative Array) where I can iterate through the key/value. Something like this:
for key in $map
do
echo key=$key value=$map
done
Sample output from the map:
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Hi,
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In the awk below I am trying to get the average of the sum of $7 if the string in $4 matches in the line below it. The --- in the desired out is not needed, it is just to illustrate the calculation. The awk executes and produces the current out. I am not sure why the middle line is skipped and the... (2 Replies)
Discussion started by: cmccabe
2 Replies
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perlcc
PERLCC(1) Perl Programmers Reference Guide PERLCC(1)NAME
perlcc - generate executables from Perl programs
SYNOPSIS
$ perlcc hello # Compiles into executable 'a.out'
$ perlcc -o hello hello.pl # Compiles into executable 'hello'
$ perlcc -O file # Compiles using the optimised C backend
$ perlcc -B file # Compiles using the bytecode backend
$ perlcc -c file # Creates a C file, 'file.c'
$ perlcc -S -o hello file # Creates a C file, 'file.c',
# then compiles it to executable 'hello'
$ perlcc -c out.c file # Creates a C file, 'out.c' from 'file'
$ perlcc -e 'print q//' # Compiles a one-liner into 'a.out'
$ perlcc -c -e 'print q//' # Creates a C file 'a.out.c'
$ perlcc -I /foo hello # extra headers (notice the space after -I)
$ perlcc -L /foo hello # extra libraries (notice the space after -L)
$ perlcc -r hello # compiles 'hello' into 'a.out', runs 'a.out'.
$ perlcc -r hello a b c # compiles 'hello' into 'a.out', runs 'a.out'.
# with arguments 'a b c'
$ perlcc hello -log c # compiles 'hello' into 'a.out' logs compile
# log into 'c'.
DESCRIPTION
perlcc creates standalone executables from Perl programs, using the code generators provided by the B module. At present, you may either
create executable Perl bytecode, using the "-B" option, or generate and compile C files using the standard and 'optimised' C backends.
The code generated in this way is not guaranteed to work. The whole codegen suite ("perlcc" included) should be considered very experimen-
tal. Use for production purposes is strongly discouraged.
OPTIONS -Llibrary directories
Adds the given directories to the library search path when C code is passed to your C compiler.
-Iinclude directories
Adds the given directories to the include file search path when C code is passed to your C compiler; when using the Perl bytecode
option, adds the given directories to Perl's include path.
-o output file name
Specifies the file name for the final compiled executable.
-c C file name
Create C code only; do not compile to a standalone binary.
-e perl code
Compile a one-liner, much the same as "perl -e '...'"
-S Do not delete generated C code after compilation.
-B Use the Perl bytecode code generator.
-O Use the 'optimised' C code generator. This is more experimental than everything else put together, and the code created is not guaran-
teed to compile in finite time and memory, or indeed, at all.
-v Increase verbosity of output; can be repeated for more verbose output.
-r Run the resulting compiled script after compiling it.
-log
Log the output of compiling to a file rather than to stdout.
perl v5.8.0 2003-02-18 PERLCC(1)