"awk command in hp UNIX subtract 30 days automatically from current date without date illegal option"

Post #303029119 by Don Cragun on Monday 21st of January 2019 06:13:07 PM

Quote:
Originally Posted by wisecracker
This is a method longhand, but I suspect it is not fully POSIX compliant.
OSX 10.14.1, default bash terminal.
Code:
Last login: Mon Jan 21 20:27:49 on ttys000
AMIGA:amiga~> less_days=30
AMIGA:amiga~> day_secs=$(( 24*60*60 ))
AMIGA:amiga~> DATE=$( date -r $(( $( date +%s )-( ${less_days}*${day_secs} ) )) )
AMIGA:amiga~> echo "${DATE}"
Sat 22 Dec 2018 20:33:03 GMT
AMIGA:amiga~> _

Hi wisecracker,
You suspected correctly. The POSIX date utility does not have a -r option and the POSIX date utility does not have a %s format specifier. There are plans to add the %s format specifier in the next revision of the standard. So far, no one has requested adding date -r to the standard.

With standard implementations of awk, you can get the number of seconds since the Epoch (i.e. midnight at the start of January 1, 1970 GMT) using the command:
Code:
awk 'BEGIN{print srand(srand())}'

The perl code that Corona688 suggested in post #17 in this thread is probably the best bet on HP-UX, but, of course, perl isn't in the standard either. Nonetheless, perl is almost surely available for HP-UX from HP even though it isn't standard.

And, kmarcus, I apologize for post #18. I had already asked that question before in post #2 a month ago and you answered it in post #3. Smilie
These 2 Users Gave Thanks to Don Cragun For This Post:
 

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