Dates specified with hyphens (-) as delimiters are assumed to be in ISO 8601 format, with the year first, therefore:
So basically 19-01-2017 does not conform to the expected format of [cc]yy-mm-dd and so was rejected.
You could use slashes (/) to delimit the day, month and year, unfortunately date will assume American date format:
Personally I would use the year-month-day format.
Andrew
These 2 Users Gave Thanks to apmcd47 For This Post:
Hi ,
I have written a shell script that takes the current date on the server and stores it in a file.
echo get /usr/home/data-`date '+%Y%d'`.xml> /usr/local/sandeep/GetFILE.ini
I call this GetFILE.ini file from an sftp program to fetch a file from /usr/home/ as location. The file is in... (3 Replies)
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
I have a list of dates in the following format: mm/dd/yyyy and want to change these to the MySQL standard format: yyyy-mm-dd.
The dates in the original file may or may not be zero padded, so April is sometimes "04" and other times simply "4".
This is what I use to change the format:
sed -i '' -e... (2 Replies)
I am testing a script and need to change the system date to Nov 30 2009. I cannot seem to find a way to do this other than TZ command but it does not seem to work correctly.
I tried TZ=GMT+168 date but it is returning todays date
Mon Dec 7 19:48:11 GMT 2009
...instead of Nov 30 2009
I... (4 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hello,
I am trying to show today's date and time in a better format than ‘date' (Using positional parameters). I found a command mktime and am wondering if this is the best command to use or will this also show me the time elapse since 1/30/70? Any help would be greatly appreciated, Thanks... (3 Replies)
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
xpnl_hypo_reu_miplvdone_11172011.csv
xpnl_hypo_reu_miplvdone_11-17-2011.csv
xpnl_hypo_reu_miplvdone_20111117.csv
xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Hi Unix Gurus,
I would like to rename several files in a Unix Directory . The filenames can have more than 1 underscore ( _ ) and the last underscore is always followed by a date in the format mmddyyyy. The Extension of the files can be .txt or .pdf or .xls etc and is case insensitive ie... (1 Reply)
Discussion started by: pchegoor
1 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)