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Top Forums Web Development Color a Badge Based on the Weeks the Member is Active in the Latest Sequence Post 303028470 by Neo on Wednesday 9th of January 2019 02:36:40 AM
Old 01-09-2019
Color a Badge Based on the Weeks the Member is Active in the Latest Sequence

Hi Ravinder,

Could you (and anyone else who wants to help out) check this PHP code and confirm it does what I expect it to do, which is to color a badge based on the weeks a member is active in the latest sequence? I did a cut-paste-change from my "days in sequence" PHP prototype script and it would be great if someone could check it.

Thanks.

Code:
<?php
$weekago = time() -  60 * 60 * 24 * 7;
$incrementseq = "UPDATE user SET lastweekactive = (UNIX_TIMESTAMP()/(60*60*24*7)), weeksinsequence =  weeksinsequence +1 WHERE userid =" . $uid;
$selectweek = "SELECT lastweekactive AS lastactive FROM user WHERE userid =" . $uid;
$resetweek = "UPDATE user SET lastweekactive = (UNIX_TIMESTAMP()/(60*60*24*7)), weeksinsequence =  1 WHERE userid =" . $uid;
$week = $vbulletin->db->query_first($selectweek);
if ($week['lastactive'] > $weekago && $week['lastactive'] <= $weekago * 2) {
    $status = $vbulletin->db->query_write($incrementseq);
} elseif ($week['lastactive'] > $weekago * 2) {
    $status = $vbulletin->db->query_write($resetweek);
}
$getseq = "SELECT weeksinsequence AS weeksactive FROM user WHERE userid =" . $uid;
$weeks = $vbulletin->db->query_first($getseq);
if ($weeks['weeksactive'] > 7) {
    $color['fahistory'] = 'black';
} elseif ($weeks['weeksactive'] > 3) {
    $color['fahistory'] = 'indigo';
} elseif ($weeks['weeksactive'] > 2) {
    $color['fahistory'] = 'blue';
} elseif ($weeks['weeksactive'] > 1) {
    $color['fahistory'] = 'limegreen';
} else {
    $color['fahistory'] = 'lightgray';
}
$badgejs .= 'badge["falaptopcode"] = "' . $color['fahistory'] . '";';
$badgejs .= 'badge["falaptopcode"] = "' . number_format($weeks['weeksactive']) . '";';

 

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PHPVERSION(3)								 1							     PHPVERSION(3)

phpversion - Gets the current PHP version

SYNOPSIS
string phpversion ([string $extension]) DESCRIPTION
Returns a string containing the version of the currently running PHP parser or extension. PARAMETERS
o $extension - An optional extension name. RETURN VALUES
If the optional $extension parameter is specified, phpversion(3) returns the version of that extension, or FALSE if there is no version information associated or the extension isn't enabled. EXAMPLES
Example #1 phpversion(3) example <?php // prints e.g. 'Current PHP version: 4.1.1' echo 'Current PHP version: ' . phpversion(); // prints e.g. '2.0' or nothing if the extension isn't enabled echo phpversion('tidy'); ?> Example #2 PHP_VERSION_ID example and usage <?php // PHP_VERSION_ID is available as of PHP 5.2.7, if our // version is lower than that, then emulate it if (!defined('PHP_VERSION_ID')) { $version = explode('.', PHP_VERSION); define('PHP_VERSION_ID', ($version[0] * 10000 + $version[1] * 100 + $version[2])); } // PHP_VERSION_ID is defined as a number, where the higher the number // is, the newer a PHP version is used. It's defined as used in the above // expression: // // $version_id = $major_version * 10000 + $minor_version * 100 + $release_version; // // Now with PHP_VERSION_ID we can check for features this PHP version // may have, this doesn't require to use version_compare() everytime // you check if the current PHP version may not support a feature. // // For example, we may here define the PHP_VERSION_* constants thats // not available in versions prior to 5.2.7 if (PHP_VERSION_ID < 50207) { define('PHP_MAJOR_VERSION', $version[0]); define('PHP_MINOR_VERSION', $version[1]); define('PHP_RELEASE_VERSION', $version[2]); // and so on, ... } ?> NOTES
Note This information is also available in the predefined constant PHP_VERSION. More versioning information is available using the PHP_VERSION_* constants. SEE ALSO
PHP_VERSION constants, version_compare(3), phpinfo(3), phpcredits(3), php_logo_guid(3), zend_version(3). PHP Documentation Group PHPVERSION(3)
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