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Top Forums Web Development Color a Badge Based on the Weeks the Member is Active in the Latest Sequence Post 303028470 by Neo on Wednesday 9th of January 2019 02:36:40 AM
Old 01-09-2019
Color a Badge Based on the Weeks the Member is Active in the Latest Sequence

Hi Ravinder,

Could you (and anyone else who wants to help out) check this PHP code and confirm it does what I expect it to do, which is to color a badge based on the weeks a member is active in the latest sequence? I did a cut-paste-change from my "days in sequence" PHP prototype script and it would be great if someone could check it.

Thanks.

Code:
<?php
$weekago = time() -  60 * 60 * 24 * 7;
$incrementseq = "UPDATE user SET lastweekactive = (UNIX_TIMESTAMP()/(60*60*24*7)), weeksinsequence =  weeksinsequence +1 WHERE userid =" . $uid;
$selectweek = "SELECT lastweekactive AS lastactive FROM user WHERE userid =" . $uid;
$resetweek = "UPDATE user SET lastweekactive = (UNIX_TIMESTAMP()/(60*60*24*7)), weeksinsequence =  1 WHERE userid =" . $uid;
$week = $vbulletin->db->query_first($selectweek);
if ($week['lastactive'] > $weekago && $week['lastactive'] <= $weekago * 2) {
    $status = $vbulletin->db->query_write($incrementseq);
} elseif ($week['lastactive'] > $weekago * 2) {
    $status = $vbulletin->db->query_write($resetweek);
}
$getseq = "SELECT weeksinsequence AS weeksactive FROM user WHERE userid =" . $uid;
$weeks = $vbulletin->db->query_first($getseq);
if ($weeks['weeksactive'] > 7) {
    $color['fahistory'] = 'black';
} elseif ($weeks['weeksactive'] > 3) {
    $color['fahistory'] = 'indigo';
} elseif ($weeks['weeksactive'] > 2) {
    $color['fahistory'] = 'blue';
} elseif ($weeks['weeksactive'] > 1) {
    $color['fahistory'] = 'limegreen';
} else {
    $color['fahistory'] = 'lightgray';
}
$badgejs .= 'badge["falaptopcode"] = "' . $color['fahistory'] . '";';
$badgejs .= 'badge["falaptopcode"] = "' . number_format($weeks['weeksactive']) . '";';

 

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PHP_CHECK_SYNTAX(3)							 1						       PHP_CHECK_SYNTAX(3)

php_check_syntax - Check the PHP syntax of (and execute) the specified file

SYNOPSIS
bool php_check_syntax (string $filename, [string &$error_message]) DESCRIPTION
Performs a syntax (lint) check on the specified $filename testing for scripting errors. This is similar to using php -l from the commandline except that this function will execute (but not output) the checked $filename. For example, if a function is defined in $filename, this defined function will be available to the file that executed php_check_syntax(3), but output from $filename will be suppressed. Note For technical reasons, this function is deprecated and removed from PHP. Instead, use php -l somefile.php from the commandline. PARAMETERS
o $filename - The name of the file being checked. o $error_message - If the $error_message parameter is used, it will contain the error message generated by the syntax check. $error_message is passed by reference. RETURN VALUES
Returns TRUE if the lint check passed, and FALSE if the link check failed or if $filename cannot be opened. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.0.5 | | | | | | | This function was removed from PHP. | | | | | 5.0.3 | | | | | | | Calling exit(3) after php_check_syntax(3) | | | resulted in a Segfault. | | | | | 5.0.1 | | | | | | | $error_message is passed by reference. | | | | +--------+---------------------------------------------------+ EXAMPLES
php -l somefile.php The above example will output something similar to: PHP Parse error: unexpected T_STRING in /tmp/somefile.php on line 81 SEE ALSO
include(3), is_readable(3). PHP Documentation Group PHP_CHECK_SYNTAX(3)
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