Sponsored Content
Top Forums Web Development Notes with Ravinder on Badging System Development Part II Post 303028185 by RavinderSingh13 on Tuesday 1st of January 2019 11:53:40 AM
Old 01-01-2019
Hello Neo,

I have created code snippet for badge for a user completing anniversary on forums. I have put a condition here which validates that if a user is NOT ACTIVE from last 1 year OR user has NOT completed a year itself, then only he should be other than RED badge. Also I have made use of your previously used variable named $time_inactive along with $year here too.

Code:
<?php
$query = "SELECT TIME_TO_SEC(TIMEDIFF(NOW(), FROM_UNIXTIME('jointime')))/(3600*24) AS 'join_time' FROM users WHERE userid =" . $uid;
$results = $db->query_first_slave($query);
if ($time_inactive < $year){
  if ($results['join_time'] > 0 && $results['join_time']<1) { 
        $color['fajoin_time'] = 'orangered'; 
  } elseif ($results['join_time']<2 && $results['join_time']>=1) {
        $color['fajoin_time'] = 'darkorange';
  } elseif ($results['join_time']<3 && $results['join_time']>=2) {
        $color['fajoin_time'] = 'lightgray';
  } elseif ($results['join_time']<4 && $results['join_time']>=3) {
        $color['fajoin_time'] = 'limegreen';
  }
    elseif ($results['join_time']<5 && $results['join_time']>=4) {
        $color['fajoin_time'] = 'blue';
  }
    elseif ($results['join_time']<10 && $results['join_time']>=5) {
        $color['fajoin_time'] = 'indigo';
  }
    elseif ($results['join_time']>=10) {
        $color['fajoin_time'] = 'black';
  }
  else  { 
    $color['fajoin_time'] = 'red'; 
  }
}
else  { 
    $color['fajoin_time'] = 'red'; 
}


$badgejs .= 'badge["fajoin_time"] = "' . $color['fajoin_time'] . '";';  
$badgejs .= 'badge["fajoin_timeval"] = "' . number_format($results['join_time']) . '";';

jQuery: I haven't changed "chess-rook" name here, you could please select it as per availability of icons.

$('.fa-chess-rook').css("color",badge["fajoin_time"]);
$('.fa-chess-rook').css("cursor","pointer").attr("title", badge["fajoin_time"] + " Days in UNIX.com forums");
$('.fa-chess-rook').closest('div').find('.fa-circle').css("color",badge["fajoin_time]);

I have checked php code's syntax on online syntax checker in link PHP Code Checker - Syntax Check for Common PHP Mistakes and it didn't find ay issues in it.

NOTE: To validate query stuff I created a dummy schema and table in my vmware test machine and filled some dummy data entry in it to check query mentioned and looked ok there.

Thanks,
R. Singh
 

3 More Discussions You Might Find Interesting

1. What is on Your Mind?

New Badging System - Badges Prototype Beta 1 (Badges Only)

Today I mapped out the new badging system using FA icons, Beta 1 in no particular order except a 6 x 8 grid: https://www.unix.com/members/1-albums215-picture991.png The prototype HTML code for this layout: <style> .fa-badge-grid { font-size: 1.5em; } .row { ... (38 Replies)
Discussion started by: Neo
38 Replies

2. What is on Your Mind?

Status of Badging System - Beta 1

Dear All, Here is the current status of the badging system: The Beta 1 phase of the new badging system is close to completion. 42 prototype badges have been "allocated" 6 prototype badge slots are held in reserve The "alert you have new badges" prototype is running and is currently... (4 Replies)
Discussion started by: Neo
4 Replies

3. What is on Your Mind?

Badging System: UNIX.COM Bug Hunter Badge (New)

I have moved the bug badge out of reserve and into the main stream. Basically, I will assign a color level like the others, based on who has made a good actionable bug report for UNIX.COM. "Good" means screenshots, links, and even details from web dev tools our the HTML source code. So far,... (0 Replies)
Discussion started by: Neo
0 Replies
EASTER_DAYS(3)								 1							    EASTER_DAYS(3)

easter_days - Get number of days after March 21 on which Easter falls for a given year

SYNOPSIS
int easter_days ([int $year = date("Y")], [int $method = CAL_EASTER_DEFAULT]) DESCRIPTION
Returns the number of days after March 21 on which Easter falls for a given year. If no year is specified, the current year is assumed. This function can be used instead of easter_date(3) to calculate Easter for years which fall outside the range of Unix timestamps (i.e. before 1970 or after 2037). The date of Easter Day was defined by the Council of Nicaea in AD325 as the Sunday after the first full moon which falls on or after the Spring Equinox. The Equinox is assumed to always fall on 21st March, so the calculation reduces to determining the date of the full moon and the date of the following Sunday. The algorithm used here was introduced around the year 532 by Dionysius Exiguus. Under the Julian Calendar (for years before 1753) a simple 19-year cycle is used to track the phases of the Moon. Under the Gregorian Calendar (for years after 1753 - devised by Clavius and Lilius, and introduced by Pope Gregory XIII in October 1582, and into Britain and its then colonies in September 1752) two correction factors are added to make the cycle more accurate. PARAMETERS
o $year - The year as a positive number. If omitted, defaults to the current year according to the local time. o $method - Allows Easter dates to be calculated based on the Gregorian calendar during the years 1582 - 1752 when set to CAL_EASTER_ROMAN. See the calendar constants for more valid constants. RETURN VALUES
The number of days after March 21st that the Easter Sunday is in the given $year. EXAMPLES
Example #1 easter_days(3) example <?php echo easter_days(1999); // 14, i.e. April 4 echo easter_days(1492); // 32, i.e. April 22 echo easter_days(1913); // 2, i.e. March 23 ?> SEE ALSO
easter_date(3). PHP Documentation Group EASTER_DAYS(3)
All times are GMT -4. The time now is 07:43 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy