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Full Discussion: Swapping lines
Top Forums Shell Programming and Scripting Swapping lines Post 303027816 by MadeInGermany on Tuesday 25th of December 2018 09:36:35 AM
Old 12-25-2018
Another attempt with awk.
Untested but well documented.
Code:
awk '
# prepend the current line to buf (ORS is a newline)
{buf=($0 ORS buf)}
# new paragraph? Then store the current line (replacing old content)
p==0 {buf=$0; p=1}
# empty line? Then print buf; new paragraph
NF==0 {print buf; p=0}
# at the END print buf if not yet printed
END {if (p==1) print buf}
' file

 

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io_waitread(3)						     Library Functions Manual						    io_waitread(3)

NAME
io_waitread - read from a descriptor SYNTAX
#include <io.h> int io_waitread(int64 fd,char* buf,int64 len); DESCRIPTION
io_waitread tries to read len bytes of data from descriptor fd into buf[0], buf[1], ..., buf[len-1]. (The effects are undefined if len is 0 or smaller.) There are several possible results: o o_waitread returns an integer between 1 and len: This number of bytes was available for immediate reading; the bytes were read into the beginning of buf. Note that this number can be, and often is, smaller than len; you must not assume that io_waitread always succeeds in reading exactly len bytes. o io_waitread returns 0: No bytes were read, because the descriptor is at end of file. For example, this descriptor has reached the end of a disk file, or is reading an empty pipe that has been closed by all writers. o io_waitread returns -3, setting errno to something other than EAGAIN: No bytes were read, because the read attempt encountered a persis- tent error, such as a serious disk failure (EIO), an unreachable network (ENETUNREACH), or an invalid descriptor number (EBADF). SEE ALSO
io_nonblock(3), io_waitread(3), io_waitreadtimeout(3) io_waitread(3)
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