I have a string "\/scratch\/databases\". I want
to have a new string "\/scratch\/databases" by cutting last '\' character using shell script. I can't do this
Please help me.
Thanks in advance
ThuongTranVN (4 Replies)
Hello All,
Plz help me with:
I have a csv file with data separated by ',' and optionally enclosed by "". I want to check each of these values to see if they exceed the specified string length, and if they do I want to cut just that value to the max length allowed and keep the csv format as it... (9 Replies)
I have a file:
chromosome1:436728
chromosome2:32892
.....
chromosome22:23781
I just want to get the number, not the prefix "chromosomeX", so I want to remove all the prefix ahead of the numbers. How can I do that?? Thanks!!! (PS: give me some very simple command so that I can understand... (4 Replies)
Hi
I am having a file with the following content(its created by ls of a directory):
-rw-r----- 1 321 321 0 Oct 14 10:41 xcv23456
-rw-r----- 1 321 321 0 Oct 14 10:41 xcv23457
-rw-r----- 1 321 321 0 Oct 14 10:41 xcv23458
-rw-r----- 1 321 321 ... (6 Replies)
I need only the last .ko files to be stripped from the whole result., ie libiscsi2.ko, scsi_transport_iscsi2.ko etc..
kernel/drivers/scsi/libiscsi2.ko
kernel/drivers/scsi/scsi_transport_iscsi2.ko
kernel/drivers/scsi/scsi_transport_iscsi.ko
kernel/fs/nls/nls_utf8.ko... (4 Replies)
hello,
i need to cut a string in unix but not from file ,, from variable, i searched on special line , and i need a specific data from this line , i get it on variable, how can i cut data that i need ??? merci (2 Replies)
Hi in a directory i've files having the following name
for_category_info_19990101984301
for_catgry_meta_19991111214601
-------
I just want the name till year and month i.e;
for_category_info_199901
for_catgry_meta_199911
How can i achieve the above string
Thanks (2 Replies)
---------- Post updated at 10:31 AM ---------- Previous update was at 10:28 AM ----------
Hello,
I am trying to get the string cut based on the following needs:
String1=Submitted request 25574824 for CONCURRENT SQLAP RUAPACTUALSEXT Y RUAPACTUALS122313100616.dat "2013/01/12 14:50:44"... (6 Replies)
Hi Guys,
I have following different lines separated by multiple spaces. And i need to cut only the time part (16:53) from the string. How can we achieve it?
remedy 29210 1 1 07:55 ? 00:06:20 /opt/bmc/java/jre1.6.0_17/bin/java -Xms1024m -Xmx2048m -XX:MaxPermSize=1024m... (12 Replies)
Hi Team,
Here's the record in a file.
abc\USER DEFINED\123\345\adf\aq1
Delimiter here is "\USER DEFINED\"
Expected output:
abc|123\345\adf\aq1
Find "\USER DEFINED\" and replace it with "|".
Can anyone please help us to fix this issue?
Please use CODE tags as required by... (5 Replies)
Discussion started by: kmanivan82
5 Replies
LEARN ABOUT PHP
cal_from_jd
CAL_FROM_JD(3) 1 CAL_FROM_JD(3)cal_from_jd - Converts from Julian Day Count to a supported calendarSYNOPSIS
array cal_from_jd (int $jd, int $calendar)
DESCRIPTION cal_from_jd(3) converts the Julian day given in $jd into a date of the specified $calendar. Supported $calendar values are CAL_GREGORIAN,
CAL_JULIAN, CAL_JEWISH and CAL_FRENCH.
PARAMETERS
o $jd
- Julian day as integer
o $calendar
- Calendar to convert to
RETURN VALUES
Returns an array containing calendar information like month, day, year, day of week, abbreviated and full names of weekday and month and
the date in string form "month/day/year".
EXAMPLES
Example #1
cal_from_jd(3) example
<?php
$today = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($today, CAL_GREGORIAN));
?>
The above example will output:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
SEE ALSO cal_to_jd(3), jdtofrench(3), jdtogregorian(3), jdtojewish(3), jdtojulian(3), jdtounix(3).
PHP Documentation Group CAL_FROM_JD(3)