Same principal approach as bakunin's, but mayhap a bit less resource consuming (no cat nor echo (i.e. opening time stamp file twice), just file system (meta data) operation, running date just once), given stat and date -d are available on your system:
I want to schedule a batch job (SQL)to run every 6 hours in Unix and the AT command syntax does not seem to cover this.
I have created a file ncd_rpt in the directory report and have given the command in this file.
at -f /report/ncd_rpt 1:00 am tomorrow
I schedule this by running
sh... (1 Reply)
Hi Folks,
I need to remove log files for six hours on Solaris. before i used to do for every 24 hours below is the code for 1 day older log files, now i tried using -mmin +360 but it says command not found.
Can someone please help me out!!!
part of the code:
LOG_FILE=`find /home/Logdir... (1 Reply)
Hi All
I have a problem, I wonder if you can help me sort it out:
I have the following entry in the cron:
00 1,13 * * * /home/report/opn_amt_gestores_credito.ksh > opn_amt_gestores_credito.log
But the entry only runs at 01:07
I have stopped the cron deamon, and started, but it still... (39 Replies)
Hi All,
new to the forum and new to Unix but I have an issue which is annoying on a new level. I have included a short and full version for anyone needing more information.
Short Version
I am running a set of scripts that work and run fine. one of the scripts arranges the first... (4 Replies)
Hi
I need to setuop a cron entry to run every 5 min, only in office hours (between 8:00AM to 18:00PM, I did the following:
0,5,10,15,20,25,30,35,40,45,50,55 8,9,10,11,12,13,14,15,16,17,18 * * * /home/xxx/zzz.ksh
But somehow does not work.
Could it be wrong? (8 Replies)
Hi,
I've written a ksh script that read a file and parse/filter/format each line. The script runs as expected but it runs for 24+ hours for a file that has 2million lines. And sometimes, the input file has 10million lines which means it can be running for more than 2 days and still not finish.... (9 Replies)
Discussion started by: newbie_01
9 Replies
LEARN ABOUT OSX
sa2
sa2(8) BSD System Manager's Manual sa2(8)NAME
sa2 -- Generate a system activity daily report file.
SYNOPSIS
/usr/lib/sa/sa2 [-dgpu] [-n mode] [-e time] [-f filename] [-i seconds] [-s time]
DESCRIPTION
The sa2 command is a shell script used to invoke the system activity reporter sar for purposes of generating the standard default daily
report file. The report file generated is, /var/log/sa/sardd where the dd represents the current day of the month. The sa2 options are the
same as those documented in sar(1).
When sa2 runs, it will also remove data and report files, found in /var/log/sa, that are more than one week old.
The sa2 command is intended to be started by cron.
EXAMPLE CRON ENTRY
# Starting at 8am collect system activity records
# every 20 minutes for 12 hours
# 20 minutes = 1200 seconds
# 12 hours with 3 samples each hour = 36 loops
0 8 * * 1-5 /usr/lib/sa/sa1 1200 36
# After the 12 hour period,
# collect a system activity report
30 20 * * 1-5 /usr/lib/sa/sa2 -A
FILES
/var/log/sa/sardd Default daily report file.
/var/log/sa/sadd Default daily data file.
dd are digits that represent the day of the month.
SEE ALSO crontab(1), fs_usage(1), netstat(1), sar(1), sc_usage(1), top(1), vm_stat(1), crontab(5), iostat(8), sa1(8), sadc(8)Mac OS X Jul 25 2003 Mac OS X