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Top Forums Programming C++ operator overloading error Post 303026996 by Corona688 on Thursday 6th of December 2018 04:06:54 PM
Old 12-06-2018
That means the expression 'str2=whatever' returns void -- or rather, returns nothing. So there's nothing to cout.

Instead have it return const myString & and at the end, put return(*this);
 

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COLLATOR_COMPARE(3)							 1						       COLLATOR_COMPARE(3)

Collator::compare - Compare two Unicode strings

	Object oriented style

SYNOPSIS
public int Collator::compare (string $str1, string $str2) DESCRIPTION
Procedural style int collator_compare (Collator $coll, string $str1, string $str2) Compare two Unicode strings according to collation rules. PARAMETERS
o $coll -Collator object. o $str1 - The first string to compare. o $str2 - The second string to compare. RETURN VALUES
Return comparison result: o 1 if $str1 is greater than $str2 ; o 0 if $str1 is equal to $str2; o -1 if $str1 is less than $str2 . On error boolean FALSE is returned. Warning This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function. EXAMPLES
Example #1 collator_compare(3)example <?php $s1 = 'Hello'; $s2 = 'hello'; $coll = collator_create( 'en_US' ); $res = collator_compare( $coll, $s1, $s2 ); if ($res === false) { echo collator_get_error_message( $coll ); } else if( $res > 0 ) { echo "s1 is greater than s2 "; } else if( $res < 0 ) { echo "s1 is less than s2 "; } else { echo "s1 is equal to s2 "; } ?> The above example will output: SEE ALSO
collator_sort(3). PHP Documentation Group COLLATOR_COMPARE(3)
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