Sponsored Content
Full Discussion: Error code with if statement
Top Forums UNIX for Beginners Questions & Answers Error code with if statement Post 303026749 by bakunin on Sunday 2nd of December 2018 04:41:11 PM
Old 12-02-2018
Quote:
Originally Posted by RudiC
I'm not familiar with neither cygwin nor vi, so I can't give you the respective commands, but I'm sure there are settings / commands in vi to make control characters visible.
Ha! Another potential prospect to convert to the cult. ;-))

The command is (in command mode type ":" to get into colon-mode and then) set list. To switch it off again type :set nolist.

bakunin

PS: in the script i oversaw another error: "if" is one time written "If" (capitalised "I"), which also leads to a syntax error.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Code checking for all values in the same if statement.

I am trying to set up a variable based on the name of the file. function script_name { if then job_name='MONITOR' return job_name; elsif then job_name='VERSION' return job_name fi } for i in `ls *log` do script_name $i done. (4 Replies)
Discussion started by: oracle8
4 Replies

2. Shell Programming and Scripting

Error with if statement..Please help

:b:hi, I have a script as given below: pr_det="1" if then awk ' BEGIN {printf("%23s","session")}' >> report.txt awk ' BEGIN {printf "\n"} ' >> report.txt else awk ' BEGIN {printf("%55s","file_dsc")} ' >> report.txt awk ' BEGIN {printf("%101s","no_recs")} '... (1 Reply)
Discussion started by: jisha
1 Replies

3. Shell Programming and Scripting

Snytax error on If Statement--help

year=`date '+%Y'` month=`date '+%m'` day=`date '+%d'` day=`expr $day - 1` case $month in 1 | 3 | 5 | 7 | 8 | 10 | 12);; if($day =7 ); then $day=6 fi 4 | 6 | 9 | 11);; if ; then $day=31 fi 2);; if ; then if ; then (2 Replies)
Discussion started by: dannyd_y
2 Replies

4. Linux

error in if statement

Hi , I am getting an error when I run the script for checking word "view" in a file . I am using if statement. like this if then VW_VAR=` cat $TN.${ecmdate}.sql1 | grep -i view | awk '{print $3}' | cut -d '.' -f2 ` echo " VW_$VW_VAR " sed -e... (16 Replies)
Discussion started by: capri_drm
16 Replies

5. Shell Programming and Scripting

Error in IF statement

HI i am getting error while executing the given statement for filename in `cat a/file.lst` do if then echo "Exit Code Description :File $filename - is missing in Input Directory" >a.log exit else count1=`awk 'END {print NR}' $filename` echo "$count1">>a.log count2=`awk 'END {print... (4 Replies)
Discussion started by: ravi214u
4 Replies

6. UNIX for Dummies Questions & Answers

error in if statement

Hi, This is my script to catch any oracle errors. In this, the $sqlerr returns ORA-01017: invalid username/password; logon denied when i specify wrong username/password the if condition is failing. how can i resolve the issue. the if statement gives error sqloutput=`sqlplus -s -L... (1 Reply)
Discussion started by: Swapna173
1 Replies

7. UNIX for Dummies Questions & Answers

if statement code syntax

Hi, can someone please tell me what is wrong with this code? I just want it to check if the file size is greater than 2000kb. if Thanks! ---------- Post updated at 09:23 PM ---------- Previous update was at 09:21 PM ---------- I should probably post the full code: #!/bin/sh... (9 Replies)
Discussion started by: Bengel
9 Replies

8. UNIX for Dummies Questions & Answers

How to use a return code in an if statement?

Hi all, After so many tries and searching online for ideas, I had trouble accomplishing this. Is it possible to do something like this in KSH to run an if statement on a return code? Unfortunately the code below fails... Would anyone know how to fix the below attempt? if "$`{pkginfo... (3 Replies)
Discussion started by: chatguy
3 Replies

9. Shell Programming and Scripting

Error in if statement

I am working on script for stale nfs. the file consists of cat data01stale.log - - - - /abcd/backup - - - - /abcd/data Script (16 Replies)
Discussion started by: nareshkumar522
16 Replies

10. UNIX for Dummies Questions & Answers

Does this statement of code mean.....

Good morning, I am 100% mew to Unix and am trying to troubleshoot why a pgm written 3 years ago, suddenly is not working properly. It is part Perl with some UNIX commands thrown in. I need to verify what the UNIX commands are doing before I can continue with my other troubleshooting. print... (7 Replies)
Discussion started by: jaacmmason
7 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 06:03 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy