Replace string of a file with a string of another file for matches using grep,sed,awk
I have a file comp.pkglist which mention package version and release . In 'version change' and 'release change' line there are two versions 'old' and 'new' Version Change: --> Release Change: -->
for every package name I need to search in /tmp directory and replace it`s version from old version to new version and old release to new release:
How can I make it work for all packages in the comp.pkglist file to replace it`s old version to new version and old release to new release in any file under the directory /tmp.
The script should :
1) Run a loop with inputs as the name of the package in the comp.pkglist.
2) It should then grep for that package name in the /tmp directory to know which file contains the package.
3) Then it should replace old version/old release of the same package with new version.
Last edited by RudiC; 11-28-2018 at 07:38 AM..
Reason: Changed ICODE to CODE tags.
Ok, I'm stumped and can't seem to find relevant info.
(I'm not even sure, I might have asked something similar before.):
I'm trying to use shell scripting/UNIX commands to extract URLs from a fairly large web page, with a view to ultimately wrapping this in PHP with exec() and including the... (2 Replies)
Hi,
i call my shell like:
my_shell "my project name"
my script:
#!/bin/bash -vx
projectname=$1
sed s/'PROJECT_NAME ='/'PROJECT_NAME = '$projectname/ <test_config_doxy >temp
cp temp test_config_doxy
the following error occurres:
sed s/'PROJECT_NAME ... (2 Replies)
Hi Everyone,
I am new to this forum and new to sed/awk programming too !!
I need to find particular string in file1(text file) and replace it with a value from another text file(file2) the file2 has only one line and the value to be replaced with is in the second column.
file 1:
(assert (=... (21 Replies)
Can someone tell me how I can do this?
e.g:
Say file1.txt contains:
today is monday
the 22 of
NOVEMBER
2010
and file2.txt contains:
the
11th
month
of
How do i replace the word NOVEMBER with (5 Replies)
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
Hi experts,
In my text file I have the following alot of lines like below.
input.k is as follows.
2684717 -194.7050476 64.2345581 150.6500092 0 0
2684718 -213.1575623 62.7032242 150.6500092 0 0
*INCLUDE
$# filename... (3 Replies)
here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb
cat dump.sql
INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
I have a file example.txt as follows :SomeTextGoesHere
$$TODAY_DT=20140818
$$TODAY_DT=20140818
$$TODAY_DT=20140818I need to automatically update the date (20140818) in the above file, by getting the new date as argument, using a shell script.
(It would even be better if I could pass... (5 Replies)
Sorry for the long/weird title but I'm stuck on a problem I have. I have this XML file:
</member>
<member>
<name>TransactionID</name>
<value><string>123456789123456</string></value>
</member>
<member>
<name>Number</name>
... (9 Replies)
Hello
Take this file...
Test01
Ref test
Version 01
Test02
Ref test
Version 02
Test66
Ref test
Version 66
Test99
Ref test
Version 99
I want to substitute every occurrence of Test{2} with a unique random number, so for example, if I was using sed, substitution would be something... (1 Reply)
Discussion started by: funkman
1 Replies
LEARN ABOUT SUNOS
regex
regex(1F) FMLI Commands regex(1F)NAME
regex - match patterns against a string
SYNOPSIS
regex [-e] [ -v "string"] [ pattern template] ... pattern [template]
DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string
against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and
returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply
returns TRUE. If no match is found, regex returns FALSE.
The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes
to turn off special meanings of characters. Note that only the final pattern in the list may lack a template.
The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through
( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so
that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and
some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9.
OPTIONS
The following options are supported:
-e Evaluates the corresponding template and writes the result to the standard output.
-v "string" Uses string instead of the standard input to match against patterns.
EXAMPLES
Example 1: Cutting letters out of a string
To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE):
`regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'`
Example 2: Validating input in a form
In a form, to validate input to field 5 as an integer:
valid=`regex -v "$F5" '^[0-9]+$'`
Example 3: Translating an environment variable in a form
In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e:
value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'`
Note the use of the pattern '.*' to mean "anything else".
Example 4: Using backquoted expressions
In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini-
tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this
example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login
ids on the system.
`cat /etc/passwd | regex '^([^:]*)$0.*$' '
name=$m0
action=`message "$m0 is a user"`'`
DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE.
NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the
$m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them.
Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam-
ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will.
The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth).
regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows:
`regex -e ...; command1; command2`
command1 and command2 would never be executed. However, dividing the expression into two:
`regex -e ...``command1; command2`
would yield the desired result.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5)SunOS 5.10 12 Jul 1999 regex(1F)