11-13-2018
Thanks a lot..Its working..
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how to match an alphanumeric string like the following.
i have to do like the following.
if the input line is
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Hi :)
I am writing a ksh
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A12B3456CD78
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Hi there
With shell script I'm trying to split the string into two parts. One is alphanumeric part, the other one is a numeric part.
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Okay I will let users input spaces as well :)
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Hi there,
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I want help to insert space between digits and letters in a alphanumeric string.
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TRY234TER
PHY1TYR
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TRY 234 TER
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#!/bin/sh
b= SERVER
if ;
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____________________________ (17 Replies)
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Hi,
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LOOK(1) BSD General Commands Manual LOOK(1)
NAME
look -- display lines beginning with a given string
SYNOPSIS
look [-df] [-t termchar] string [file]
DESCRIPTION
The look utility displays any lines in file which contain string as a prefix. As look performs a binary search, the lines in file must be
sorted.
If file is not specified, the file /usr/share/dict/words is used, only alphanumeric characters are compared and the case of alphabetic char-
acters is ignored.
Options:
-d Dictionary character set and order, i.e. only alphanumeric characters are compared.
-f Ignore the case of alphabetic characters.
-t Specify a string termination character, i.e. only the characters in string up to and including the first occurrence of termchar are
compared.
The look utility exits 0 if one or more lines were found and displayed, 1 if no lines were found, and >1 if an error occurred.
FILES
/usr/share/dict/words the dictionary
COMPATIBILITY
The original manual page stated that tabs and blank characters participated in comparisons when the -d option was specified. This was incor-
rect and the current man page matches the historic implementation.
SEE ALSO
grep(1), sort(1)
HISTORY
look appeared in Version 7 AT&T UNIX.
BSD
June 14, 1993 BSD