First my apologize for not putting the actual data.
The Year I should take will always be on column 4. in the above scenario. We are having as P201835. The column I need check the do the subtraction is 2,4,10
I tried changing the awk code like this and ran. It give me the same output as original and no change
Last edited by arunkumar_mca; 11-02-2018 at 12:14 PM..
Hi i am trying to subtract days from current date. For example todays date is 10/03/2006. If i subtract 2 days it should give 8/03/2006. I am also trying to find the access date of a file in dd/mm/yyyy format. Can any one please help in how to do this.
Ramesh (1 Reply)
I have looked through the forums and found many date / time manipulation tools, but cannot seem to find something that fits my needs for the following.
I have a log file with date time stamps like this:
Jun 21 17:21:52
Jun 21 17:24:56
Jun 21 17:27:59
Jun 21 17:31:03
Jun 21 17:34:07
Jun... (0 Replies)
Dear Expert,
Is there a command to do that in Unix?
In such a way that we don't need to actually "write" or
modified the content.
-- monkfan (4 Replies)
how can we add or subtract days from the output of date command in unix...
like if i want to subtract a day from the result of date command like this..
v_date=`date +%Y%m%d`
this wud give me 20080519
now i want to subtract one day from this.. so tht it wud give me 20080518..
how do i do... (1 Reply)
Hi all,
I'm using Red Hat Linux and want to move some folders and files around but not change the modified date. Is this possible?
I know cp has a -p flag which seems to do what I want, but this is a large volume of data so copying and deleting would not be feasible. (13 Replies)
I got a statement like below to subtract 1 from given date using teradata. I am looking for a one line unix command to perform the same.
select 'parse_this_record', (DATE '${FILE_DATE}' - 1) (FORMAT 'YYYY-MM-DD');
Input: 2012-02-21
Expected Output: 2012-02-20
PS: One liner because I am... (2 Replies)
I have a CSV file with a date format like this;
11/19/2012 17:37:00,1.372,121.6
11/19/2012 17:38:00,0.743,121.6
Want to change the time stamp to seconds after 1970 so I can get the data in rrdtool. For anyone interested, this is data from a TED5000 unit and is Kwatts and volts.
Needs to... (3 Replies)
Hi All,
I am getting a date from environment variable and want to do some processing by subtracting 2 months from the date passed through the environment variable.
I am trying the following syntax :
date_var=2014-08-31
date_2M_ago='$date_var+"%d%m%y" --$date_var="2 months ago" '... (3 Replies)
I am trying to achieve to get only the month and the day. Example Feb 5 (as you can see if it is feb 1-9) the space is 2. If it is feb 10-28, the space is only 1. I am trying to right a script that will list a directory and shoot an email if there is an activity in last 7 days. I dont really trust... (5 Replies)
Discussion started by: invinzin21
5 Replies
LEARN ABOUT DEBIAN
mongoexport
MONGOEXPORT(1) Mongo Database MONGOEXPORT(1)NAME
mongoexport - the Mongo export tool
SYNOPSIS
mongoexport [OPTIONS]
DESCRIPTION
mongoexport is a tool to export a MongoDB collection to either JSON or CSV. The query can be filtered or a list of fields to output can be
given.
If the output is CSV, the fields must be specified in order.
EXAMPLES
mongoexport -d test -c test1 --csv -f name,num
export documents from test.test1 in CSV format
OPTIONS --help show usage information
-h, --host HOST
server to connect to (default HOST=localhost)
-d, --db DATABASE
database to use
-c, --c COLLECTION
collection to use
-q, --query QUERY
query filter
-f, --fields FIELDS
comma-separated list of field names
--csv export to CSV instead of JSON
-o, --out FILE
output file, if not specified, stdout is used
--dbpath PATH
directly access mongod data files in this path, instead of connecting to a mongod instance
COPYRIGHT
Copyright 2007-2009 10gen
SEE ALSO
For more information, please refer to the MongoDB wiki, available at http://www.mongodb.org.
AUTHOR
Kristina Chodorow
10gen June 2009 MONGOEXPORT(1)