11-02-2018
Sorry, for the most part i thought i understood your goal, but i am a bit confused:
Quote:
Originally Posted by
arunkumar_mca
and find if the year is >= 20152 .
Is that simply a typo or can the week numbers be either one or two digits? Is the value above in fact reading "201502" or "20152x" or could the second week in 2015 be both represented by "201502" or "20152"?
Either way, it is easily done in awk, but with different algorithms, obviously.
bakunin
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