Let me explain you clearly. The expectation of script_1 - every month 25th it would run. Script_2 - every day and script_3 every quarterly month end. For eg. if script_1 fails due to any reason on 25th and if i re-run the main_script on 26th. In this scenario script_1 will not run on 26th but i would like to run on 26th because it failed on 25th but i tried re-running on next day or any other day on same month, if i re-run the main_Script for that month then it should script_1 should run. In this scenario if i take script_2 which runs every day shouldn't run for again because it was already successful on 25th daily run
If you want to force the main script to run script_1 learn about getopt/getopts and put in a flag to force the running of script_1:
Now if the date is not the 25th you check to see whether ${force_script1} is set to "true" (the string, not the boolean).
I don't understand why you don't want to run script_2 if you are having to rerun script_1. It's a different day; you are running script_2 daily. Right? Unless the main script is being run daily from cron?
And there is this:
Quote:
In this scenario if i take script_2 which runs every day shouldn't run for again because it was already successful on 25th daily run
which implies that script_2 should not run EVER on the 26th because it ran successfully on the 25th!
Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
hi all
i need a script which will find all the processes witht the name of xxx and kill all those processes that runs for more than 1 day.
Regards (3 Replies)
Hi,
I would like to write a script that checks if a file ('counter') was modified the previous day, if so erase its contents and write 00000000 into it.
For e.g. if the file 'counter' was last modified at 11.30pm on 24th May and the script runs at 12.15am of 25th May, it should erase it's... (1 Reply)
Hello Experts,
I have a script which i want to run the on last day of every month.
let say I have backup.sh script which i want to run it every month last day.
Can anyone please help :confused:
thanks (4 Replies)
Hi all,
I currently have a UNIX file maintenance script that runs daily as a cron job.
Now I want to change the script and create functions/sub inside it that runs on a weekly or monthly basis.
To run all the scripts' daily maintenance, I want to schedule it in cron as simply maint.sh... (1 Reply)
Hi,
I want to run a job in cron on a specific date(say 25th of every month) excluding holidays. Can anyone provide some hints to do this? Thanks for any inputs. (1 Reply)
I am looking for a unix script which could run a job on 2, 4 and 7 working day of the month.
if the days are falling on the saturday/sunday. it should run on the next day.
Thank you.. (9 Replies)
Discussion started by: tradingspecial
9 Replies
LEARN ABOUT DEBIAN
sa2
SA2(8) Linux User's Manual SA2(8)NAME
sa2 - Write a daily report in the /var/log/sysstat directory.
SYNOPSIS
/usr/lib/sysstat/sa2
DESCRIPTION
The sa2 command is a shell procedure variant of the sar command which writes a daily report in the /var/log/sysstat/sardd file, where the
dd parameter indicates the current day. The sa2 command handles all of the flags and parameters of the sar command.
The sa2 command is designed to be started automatically by the cron command.
EXAMPLES
To run the sa2 command daily, place the following entry in your root or adm crontab file:
5 19 * * 1-5 /usr/lib/sysstat/sa2 -A &
This will generate a daily report called /var/log/sysstat/sardd It will also remove reports more than one week old.
Debian note
The Debian sysstat package has already placed such an entry in your system crontab. Please refer to the /usr/share/doc/sys-
stat/README.Debian file for details.
FILES
/var/log/sysstat/sardd
Indicate the daily report file, where the dd parameter is a number representing the day of the month.
AUTHOR
Sebastien Godard (sysstat <at> orange.fr)
SEE ALSO sar(1), sadc(8), sa1(8), sadf(1)
http://pagesperso-orange.fr/sebastien.godard/
Linux AUGUST 2010 SA2(8)