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Shell Programming and Scripting
How to control grep output intact for each matching line?
Post 303024541 by Corona688 on Wednesday 10th of October 2018 01:43:41 PM
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I have a script that sorta works the way I want but I would rather
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Hi all,
I want to display line number for matching string in a file. can anyone please help me.
I used
grep -n "ABC" file
so it displays
6 ABC.
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I have a file with a list of references towards the end and want to apply a grep for some string.
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@unnumbered References
@sp 1
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LEARN ABOUT NETBSD
zegrep
ZGREP(1) BSD General Commands Manual ZGREP(1) NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD