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Top Forums Shell Programming and Scripting Convert rows into columns and create table with awk Post 303024206 by Don Cragun on Wednesday 3rd of October 2018 04:13:46 AM
Old 10-03-2018
Quote:
Originally Posted by rprpr
Thank you so much rdrtx1 for your help. I still see one issue when the total no. of fields are not equal (i.e.4 fields) for every section.. This is the output results I'm getting after I run command..Here you can see Last name is repeating for all 3 rows and Age 50 is also repeating in this below results
Code:
First Name   Last Name   Age   Country
John F         Slater           31    USA
Mark           Slater           35     United Kingdom
Jim             Slater           50     Germany
Mike           Crown           50     Canada

This is my original input file:
Code:
First Name: John F
Last Name: Slater
Age: 31
Country: USA

Last Name: Watt
Age: 35
Country: United Kingdom
First Name: Mark

Country: Germany
First Name: Jim
Age: 50

Country: Canada
Last Name:  Crown
First Name: Mike

Can you guys please suggest how to make this happen? Thank you

------ Post updated at 02:21 AM ------

I was running this below awk command initially in the first place...But this is not working either..

Code:
cat infile.txt | awk '
                        BEGIN {printf("FIRSTNAME LASTNAME AGE COUNTRY\n")
                                        }
                        /First Name:/ {F=$3$4}
                        /Last Name:/ {L=$3}
	        /Age:/ {A=$2}
                        /Country/ {print F, L, A, $2$3}' | column -t


=======================

The output results I get by running above awk command. How can I fix this? Please help. Thanks

Code:
FirstName LastName Age Country
JohnF Slater      USA
JohnF Slater   United Kingdom
Mark Slater  Germany
Jim Slater Canada

Moderator's Comments:
Mod Comment Please use CODE tags when displaying sample input, sample output, and code segments (as required by forum rules).
If you want our help, you would do well to provide the information we need to help you (such as was requested two days ago in post #4 in this thread. Since you have chosen to withhold much of the information requested, I will show you code that works with the ksh, awk, and column that are available on macOS High Sierra version 10.13.6. If there are any changes needed to work in your environment, it will be up to you to figure out what changes are needed.

Note that I added the "none given" as data to fill fields that contained no data in an input record because the version of column on my system doesn't seem to recognize two adjacent field separators as delimiters for an empty field.

I have no idea where the Last Name "Peterson" that you said should appear in the last line of your output came from. That name does not appear anywhere in any of the sample input files you have shown us. And, since there were four records in your sample input, I do not understand why your desired sample output only contained three records (not counting the header record).

On my system, when file contains the sample input you provided in post #6, the following code:
Code:
#!/bin/ksh
awk '
BEGIN {	FS = ": |\n"
	OFS = ":"
	RS = ""
	print FNn = "First Name", LNn = "Last Name", An = "Age", Cn = "Country"
}
{	A = C = F = L = "none given"
	for(i = 1; i <= NF; i += 2) {
		if($i == An)
			A = $(i + 1)
		else if($i == Cn)
			C = $(i + 1)
		else if($i == FNn)
			F = $(i + 1)
		else if($i == LNn)
			L = $(i + 1)
	}
	print F, L, A, C
}' file | column -s: -t

produces the output:
Code:
First Name  Last Name   Age         Country
John F      Slater      31          USA
Mark        Watt        35          United Kingdom
Jim         none given  50          Germany
Mike         Crown      none given  Canada

Note that the last name "Crown" in the last output record is misaligned because there is an extraneous <space> character before "Crown" in your sample input file.
 

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