When I create a newfile, I am using the filename as a variable to create the new filename. When I ouput it, the filename contains the file extension in the middle of the file
example:
router1.txtshcdpneighbors.txt
router2.logshcdpneighbors.txt
My initial approach was to strip it out, now I would like to strip out .txt or .log. How can I add an or statement to the for in statement?
If have
var='$variable'
how can I expand $variable.
I have tried many thing like duble quotes/braces etc, but nothing worked.
I need the solution ASAP. (2 Replies)
Sorry for such a dreadful title, but I'm not sure how to be more descriptive. I'm hoping some of the more gurutastic out there can take a look at a solution I came up with to a problem, and advice if there are better ways to have gone about it.
To make a long story short around 20K pieces of... (2 Replies)
I'm trying to understand if it's possible to create a set of variables that are numbered based on another variable (using eval) in a loop, and then call on it before the loop ends.
As an example I've written a script called question (The fist command is to show what is the contents of the... (2 Replies)
Hi,
I'm using a for loop reading from an input file that contains files, whose path includes a variable name.
But the for loop doesn't expand the variable and therefore can't find the file.
Here's an example:
File BACKUPFILES
/home/John/alpha
/home/Sue/beta... (8 Replies)
I need some help to write a ksh script.
My code so far (pretty bad, sorry):
#! /bin/ksh
echo "Calculate average"
UserDecision=y
while test $UserDecision = y
do
echo "Enter a number: "
read Number1
echo "Enter a number: "
read Number2
echo "Do you want to enter another number?... (2 Replies)
Hi I want to write a script such that when executed, it will store all input as different variable, for eg
./store.sh name1 name2 name3 name4
will result in
$1=name1
$2=name2
$3=name3
etc
How do I do that?
Thanks. (1 Reply)
Hi,
I have done the scripting such that it will read input line by line from a txt file and is passed through a script, but now my requirement is to pass two variables into a script from a file, how could I do this or is there any other better idea ?
for reading singe input from a file, line... (4 Replies)
Hi All,
I have to insert 2 values to a text file in specific places. I have been able to extract each variable value via a script but am not able to send these variable values to the text file.
Pasted is the script for extracting the variable values:
for i in `ls -1` ... (2 Replies)
Hello all,
I've been out of programming for awhile so sorry about the stupid, elementary question.
I'm trying to read two inputs and compare them to a list entered as a parameter via the terminal. The script is
#!/bin/bash
read -p "Enter the numbers" NUM1 NUM2
for VALUE in $@; do
... (6 Replies)
Hi guys!
Kind of new to bash scripting and now I'm stuck.
I need to curl with these variables:
"{ \"nodename\": \"$1\", \"ipaddress\": \"$2\", \"poolname\": \"$3\", \"port\": \"$4\", \"loadbalancer\" : \"$5\" }"
and my input_file.txt contains
server001 10.10.10.01 serverpool1 80... (4 Replies)
Discussion started by: yort
4 Replies
LEARN ABOUT PHP
ziparchive.addfile
ZIPARCHIVE.ADDFILE(3) 1 ZIPARCHIVE.ADDFILE(3)ZipArchive::addFile - Adds a file to a ZIP archive from the given path
SYNOPSIS
bool ZipArchive::addFile NULL (string $filename, [string $localname], [int $start], [int $length])
DESCRIPTION
Adds a file to a ZIP archive from a given path.
PARAMETERS
o $filename
- The path to the file to add.
o $localname
- If supplied, this is the local name inside the ZIP archive that will override the $filename.
o $start
- This parameter is not used but is required to extend ZipArchive.
o $length
- This parameter is not used but is required to extend ZipArchive.
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
This example opens a ZIP file archive test.zip and add the file /path/to/index.txt. as newname.txt.
Example #1
Open and add
<?php
$zip = new ZipArchive;
if ($zip->open('test.zip') === TRUE) {
$zip->addFile('/path/to/index.txt', 'newname.txt');
$zip->close();
echo 'ok';
} else {
echo 'failed';
}
?>
NOTES
Note
When a file is set to be added to the archive, PHP will lock the file. The lock is only released once the ZipArchive object has
been closed, either via ZipArchive::close or the ZipArchive object being destroyed. This may prevent you from being able to delete
the file being added until after the lock has been released.
PHP Documentation Group ZIPARCHIVE.ADDFILE(3)