i am stuck with production issue need help urgently .
Don you said finding 01,03,05,07,10,11 at 9th an 10th position in a string is easy .. can you give me sed command for it please?
------ Post updated at 11:08 PM ------
I tried Rudi's command on sun solaris, Linux . .also not working .
If you can give me this solution on solaris or Linux its also fine for me
Code:
oracle$ sed -E '/^[0-9]{8}(0[1357]|1[01])/!d'
sed: illegal option -- E
oracle$ uname -a
SunOS 5.11 11.3 sun4v sparc sun4v
$
Code:
[oracle ~]$ uname -a
Linux 004160PZ000 2.6.18-92.el5 #1 SMP Tue Apr 29 13:16:15 EDT 2008 x86_64 x86_64 x86_64 GNU/Linux
[oracle ~]$ sed -E '/^[0-9]{8}(0[1357]|1[01])/!d' a.txt
sed: invalid option -- E
------ Post updated at 11:47 PM ------
Quote:
Originally Posted by RudiC
In your regex, you want [ICODE
00[/ICODE] in positions 9 and 10. And, you may want to reread the regex documentation, as (man regex): So your bracket expr. seems to have too large a list, including 0 and , . On top, you are deleting the matching lines, so reverse the effect. Try instead:
Code:
sed '/^[0-9]\{8\}\(0[1357]\|1[01]\)/!d' file
or, for better readability
Code:
sed -E '/^[0-9]{8}(0[1357]|1[01])/!d' file
I tried your command on unix and its returning me the strings that have valid numbers at 9th and 10th position e.g "01","03","05","07","10","11" ,
I want only the three records from this file that have "33" ,"17" and "00" at 9th and 10th position.
operating system is sun solaris and Linux .
Code:
oracle:$ sed '/^[0-9]\{8\}\(0[1357]\|1[01]\)/d' a.txt
000000001000
433483433339 <<< want this to be spitted out by sed 33 at 9th n 10th pos
121121211100
167710001710 <<< want this to be spitted out by sed 17 at 9th and 10th pos
167735250310
167735260510
167735280710
167735301010
167735431010
167735451010
167710101110
167730691110
167730600000 <<< want this to be spitted out by sed 00 at 9th and 10th pos
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Last edited by RudiC; 09-27-2018 at 04:38 AM..
Reason: Added CODE tags.
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