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Top Forums Shell Programming and Scripting Number of words in line, while loop, search and grep Post 303023908 by Peasant on Tuesday 25th of September 2018 11:33:44 AM
Old 09-25-2018
Well that's just a clutter of GNU greps in broken loops to be sincere.

Assumptions are made that line with number always start with number or a + sign.

Give this a shot :
Code:
awk 'FNR==NR { person[$0]; next } /^[0-9]|+/ { number=$0 } $0 in person { printf ("%s\n%s\n", $0, number) } ' fileA fileB > fileC

Try to use awk for such assignments, it will prove irreplaceable and fast.

Also baris35 after 200 posts, a more sane approach to coding and asking questions would be advised.
Looks like you didn't even read the questions from other posters, just added 5 if's without any consideration / thinking or reading about it.
They could have just as well pasted an awk line to solve your problem (probably better then mineSmilie ), but we are here to try to make you think about a problem yourself.

Hope that helps.
Regards
Peasant.
These 2 Users Gave Thanks to Peasant For This Post:
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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