Sponsored Content
Top Forums Shell Programming and Scripting Cut command with dynamic passing of delimiter and position values Post 303022997 by Don Cragun on Monday 10th of September 2018 09:43:58 AM
Old 09-10-2018
Moderator's Comments:
Mod Comment Thread title changed from "Cut command with dynamic passing of delimited and postition value" hoping to get a better chance of finding other threads with related topics.
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Dynamic delimiter in cut command

hello.. my prob is as follows: i have to read from a file which may have different formats depending upon the delimiter used in the data of the file.now i need that the user input the delimiter.the input delimiter is stored in a variable and is used on cut command to retrieve necessary... (3 Replies)
Discussion started by: tej.buch
3 Replies

2. UNIX for Dummies Questions & Answers

scripting: multiple values from file passing to command

one of my colleagues has this question. he has a command, C_CMD which accepts 4 variables, $1 $2 $3 $4 he wants to load up a file with multiple rows, one row per set of variables and then iteratively execute the command based on the content of the file. example: at the command line you'd... (5 Replies)
Discussion started by: LisaS
5 Replies

3. UNIX for Advanced & Expert Users

How can I use double character delimiter in the cut command

Hi All, Can the cut command have double character delimiter? If yes, how can we use it. if my data file contains : apple || mango || grapes i used cut -f1 -d"||" filename but got an error. Plz help.... Thanks. (1 Reply)
Discussion started by: AshishK
1 Replies

4. Shell Programming and Scripting

passing a list of dynamic names to a "PS" command in shell script?

Hi, I am new to shell script. This is my first post .I have written a small script which returns list of names starts with "ram" in /etc/passwd .Here is that:- #!/bin/ksh NAME_LIST="name_list.txt" cat /dev/null > $NAME_LIST evalcmd="cat /etc/passwd | grep "^ram?*" | cut -d: -f1" eval... (3 Replies)
Discussion started by: sachin.tendulka
3 Replies

5. Shell Programming and Scripting

passing variable values to awk command

Hi, I have a situation where I have to specify a different value to an awk command, I beleive i have the gist of this done, however I am not able to get this correct. Here is what I have so far echo $id 065859555 This value occurs in a "pipe" delimited file in postition 8. Hence I would... (1 Reply)
Discussion started by: jerardfjay
1 Replies

6. Shell Programming and Scripting

CUT command delimiter in reverse

Hi, I've a situation where, a=xxx.yyy.zzz.txt EXTN=`echo $a | cut -d . -f2` Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do... (6 Replies)
Discussion started by: skcvasanth
6 Replies

7. UNIX for Dummies Questions & Answers

set output delimiter as tab in cut command

I can not make it work, it prints \t rather than introduce tabs. cut -d "," -f 4,8 Samples.csv --output-delimiter="\t" | sort > out Since I am running this command within a shell script, I tried manually inserting tab in this command, still does not work. I am using bash shell Suggestions... (8 Replies)
Discussion started by: analyst
8 Replies

8. Shell Programming and Scripting

How to cut by delimiter, and delimiter can be anything except numbers?

Hi all, I have a number of strings like below: //mnt/autocor/43°13'(33")W/ and i'm trying to get the numbers in this string, for example 431333 please help thanks ahead (14 Replies)
Discussion started by: sunnydanniel
14 Replies

9. Shell Programming and Scripting

Passing an argument to cut command

Can we pass an argument to cut command as below Suppose cut command is used in for or while loop and we need to pass the incremental counter cut -f$i Here $i is an argument. Like wise it has to come cut -f1 cut -f2 Where i=1,2,3,.... (1 Reply)
Discussion started by: bashamsc
1 Replies

10. Shell Programming and Scripting

Problem in using cut command with pipe as a delimiter while using in a script

There is a text file in my project named as "mom.txt" in which i want to have contents like.................. LSCRM(Application Name): 1: This is my first application. 2: Today we did shell scripting automation for this app. 3: It was really a good fun in doing so. 4: Really good.| (Here i... (7 Replies)
Discussion started by: Abhijeet Anand
7 Replies
libapache2-mod-perl2-2.0.7::docs::api::Apache2::FilterReUsermContributed Perl Documelibapache2-mod-perl2-2.0.7::docs::api::Apache2::FilterRec(3pm)

NAME
Apache2::FilterRec - Perl API for manipulating the Apache filter record Synopsis use Apache2::Filter (); use Apache2::FilterRec (); my $frec = $filter->frec; print "filter name is:", $frec->name; Description "Apache2::FilterRec" provides an access to the filter record structure. The "Apache2::FilterRec" object is retrieved by calling "frec()": $frec = $filter->frec; API
"Apache2::FilterRec" provides the following functions and/or methods: "name" The registered name for this filter $name = $frec->name(); obj: $frec ( "Apache2::FilterRec object" ) ret: $name (string) since: 2.0.00 mod_perl filters have four names: modperl_request_output modperl_request_input modperl_connection_output modperl_connection_input You can see the names of the non-mod_perl filters as well. By calling "$filter->next->frec->name" you can get the name of the next filter in the chain. Example: Let's print the name of the current and the filter that follows it: use Apache2::Filter (); use Apache2::FilterRec (); for my $frec ($filter->frec, $filter->next->frec) { print "Name: ", $frec->name; } See Also mod_perl 2.0 documentation. Copyright mod_perl 2.0 and its core modules are copyrighted under The Apache Software License, Version 2.0. Authors The mod_perl development team and numerous contributors. perl v5.14.2 2011-02-08 libapache2-mod-perl2-2.0.7::docs::api::Apache2::FilterRec(3pm)
All times are GMT -4. The time now is 03:01 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy