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Top Forums UNIX for Beginners Questions & Answers Extract part of $USER in script Post 303022354 by sheltie042 on Thursday 30th of August 2018 02:17:42 PM
Old 08-30-2018
Extract part of $USER in script

I need to be able to say "My name is $USER' when I use echo it work, when I use printf it print more 'my last name@.........'. How can I get just the part before the @ sign. I have to use printf. using UNIX.

------ Post updated at 01:17 PM ------

I used the activation code but I still can't post. Im taking a class and really need help.
 

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GRUB-RENDER-LABEL(1)                                               User Commands                                              GRUB-RENDER-LABEL(1)

NAME
grub-render-label - generate a .disk_label for Apple Macs. SYNOPSIS
grub-render-label [OPTION...] [OPTIONS] DESCRIPTION
Render Apple .disk_label. -b, --bgcolor=COLOR use COLOR for background -c, --color=COLOR use COLOR for text -f, --font=FILE use FILE as font (PF2). -i, --input=FILE read text from FILE. -o, --output=FILE set output filename. Default is STDOUT -t, --text=STRING set the label to render -v, --verbose print verbose messages. -?, --help give this help list --usage give a short usage message -V, --version print program version Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options. REPORTING BUGS
Report bugs to <bug-grub@gnu.org>. SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly installed at your site, the command info grub-render-label should give you access to the complete manual. grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)
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