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Top Forums Programming Logical Error With Type Conversion In C Post 303021962 by Corona688 on Tuesday 21st of August 2018 03:03:49 PM
Old 08-21-2018
Quote:
Originally Posted by Azrael
Very odd. I had tried using letters in place of the numbers I had in the switch/case before, but I could not get it to work.
Single and double quotes are very different things in C. In C, "A" means a string -- amounting to the array { 'A', '\0' }. And 'A' is just the number 65.

Quote:
If I print out the m_array with something like this:

Code:
for (i = 0; i < DATA_SIZE; i++){
            printf("%x\n", m_array[i]);
    }


I get back an array of random numbers that I generated from another function:

Code:
 ./test | tail 
8885ffc9
77a822d5
bf34d05d
bc229af3
fc171fb9
ab7d3609
4815ef59
83facdc3
7d77bf58
881d17ea

Then I have another function that should randomly select an element from that array, or for any of the arrays from characters that match, and use one number to replace the letter given. Sorry if that wasn't clear.
Numbers that large won't fit in your input array. chars are numbers, but their range is only -128 through +127. It'll work fine if you use a separate array of type 'int' output.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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