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Full Discussion: Logical Error With Type Conversion In C
Top Forums Programming Logical Error With Type Conversion In C Post 303021933 by Azrael on Monday 20th of August 2018 07:05:32 PM
Old 08-20-2018
Very odd. I had tried using letters in place of the numbers I had in the switch/case before, but I could not get it to work. Now it works with the exert I provided earlier. I didn't show in that exert, but I also included digits, letters and special characters with the rest of the code. Perhaps I just didn't escape some special character properly, but I can come back to that later.

If I print out the m_array with something like this:

Code:
for (i = 0; i < DATA_SIZE; i++){
            printf("%x\n", m_array[i]);
    }


I get back an array of random numbers that I generated from another function:

Code:
 ./test | tail 
8885ffc9
77a822d5
bf34d05d
bc229af3
fc171fb9
ab7d3609
4815ef59
83facdc3
7d77bf58
881d17ea


Then I have another function that should randomly select an element from that array, or for any of the arrays from characters that match, and use one number to replace the letter given. Sorry if that wasn't clear.

With using the characters in the switch/case I guess the whole conversion of char arrays to ints won't be needed. I could just create a new array with the numbers that are switched for the letters I guess.


I'm sure you're right about this part, but I'd like to understand why:

Code:
data[j] = ranit(m_array);


That function should just grab one random element that's a number from the m_array. I guess I'm assigning it wrong there?
 

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