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Top Forums UNIX for Beginners Questions & Answers find pattern matches in consecutive lines in certain fields-awk Post 303021491 by MadeInGermany on Friday 10th of August 2018 12:41:16 PM
Old 08-10-2018
What behavior do you want with the following input file?
Code:
PS012,004 SP>                 0   2 -1 -1 -1 12 -1   -1 -1  3  1     3   2   0  -1      -1      -1      -1   -1   -1    -1
PS012,004 PLG                 0   1  6 18  1 12 -1   62 -1  3  1     3  13  -2   2      -1      -1      -1  -11  500     0
PS012,004 HJN                 0   7 -1 -1 -1 -1 -1   -1  3  3  1    -1   7   2   2      -1      -1      -1    0  503     0

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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