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Full Discussion: Transpose from row to column using timestamp in first column
Top Forums Shell Programming and Scripting Transpose from row to column using timestamp in first column Post 303021289 by jiam912 on Tuesday 7th of August 2018 04:09:24 PM
Old 08-07-2018
Transpose from row to column using timestamp in first column
Gents,

Transpose from row to column, taking in consideration the first column, which contends the date.

Input file

Code:
72918,111000009,111000009,111000009,111000009,111000009,111000009,111000009,111000009,111000009
72918,2356,2357,2358,2359,2360,2361,2362,2363,2364
72918,0,0,0,0,0,0,0,0,0
72918,0,0,0,0,0,0,1,0,0
72918,1496,1502,1752,1752,1752,1752,1751,974,972
73018,111000004,111000005,111000003,111000002,111000009,111000009,111000009,111000009,111000009
73018,2349,2350,2351,2352,2353,2354,2355,2356,2357
73018,0,0,0,0,0,0,0,0,0
73018,0,0,0,0,0,0,0,0,0
73018,1524,1526,1752,1752,1752,1752,1752,256,250


Output desired

Code:
72918,111000009,2356,0,0,1496
72918,111000009,2357,0,0,1502
72918,111000009,2358,0,0,1752
72918,111000009,2359,0,0,1752
72918,111000009,2360,0,0,1752
72918,111000009,2361,0,0,1752
72918,111000009,2362,0,1,1751
72918,111000009,2363,0,0,974
72918,111000009,2364,0,0,972
73018,111000004,2349,0,0,1524
73018,111000005,2350,0,0,1526
73018,111000003,2351,0,0,1752
73018,111000002,2352,0,0,1752
73018,111000009,2353,0,0,1752
73018,111000009,2354,0,0,1752
73018,111000009,2355,0,0,1752
73018,111000009,2356,0,0,256
73018,111000009,2357,0,0,250

With this code i get the output desired, but the number of fields in the input need to the same within each block

Code:
awk -F, '
 func init_block() {ts=$1;delete a;cnt=0;nf0=NF}
 func dump_block() {for(f=2;f<=nf0;f+=1){printf("%s",ts);for(r=1;r<=cnt;r+=1){printf(",%s",a[r,f])};print ""}}
 BEGIN{ts=-1}
 ts<0{init_block()}
 ts!=$1{dump_block();init_block()}
 {cnt+=1;for(f=1; f<=NF; f++) a[cnt,f]=$f}
 END{dump_block()}' <input.txt >output.txt

Is there other option code to get the results even if the fields are not the same?

Thanks in advance
Last edited by jiam912; 08-08-2018 at 06:14 PM..
 

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LEARN ABOUT CENTOS

spi_modifytuple

SPI_MODIFYTUPLE(3)					  PostgreSQL 9.2.7 Documentation					SPI_MODIFYTUPLE(3)

NAME

       SPI_modifytuple - create a row by replacing selected fields of a given row

SYNOPSIS

       HeapTuple SPI_modifytuple(Relation rel, HeapTuple row, int ncols,
				 int * colnum, Datum * values, const char * nulls)

DESCRIPTION

       SPI_modifytuple creates a new row by substituting new values for selected columns, copying the original row's columns at other positions.
       The input row is not modified.

ARGUMENTS

       Relation rel
	   Used only as the source of the row descriptor for the row. (Passing a relation rather than a row descriptor is a misfeature.)

       HeapTuple row
	   row to be modified

       int ncols
	   number of column numbers in the array colnum

       int * colnum
	   array of the numbers of the columns that are to be changed (column numbers start at 1)

       Datum * values
	   new values for the specified columns

       const char * Nulls
	   which new values are null, if any (see SPI_execute_plan for the format)

RETURN VALUE

       new row with modifications, allocated in the upper executor context; NULL only if row is NULL

       On error, SPI_result is set as follows:

       SPI_ERROR_ARGUMENT
	   if rel is NULL, or if row is NULL, or if ncols is less than or equal to 0, or if colnum is NULL, or if values is NULL.

       SPI_ERROR_NOATTRIBUTE
	   if colnum contains an invalid column number (less than or equal to 0 or greater than the number of column in row)

PostgreSQL 9.2.7						    2014-02-17							SPI_MODIFYTUPLE(3)
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