Very simple, just bash arithmetics, no date functionality, doesn't cross hour nor midnight boundaries, relies on only full minutes being used / searched:
If your grep allows for extended regexes (-E option), drop the double backslashes.
I need to know if anyone can assist me on how to grab the last (we'll just say "x" minutes) of a log file. How do you tell the grep command without specifying an exact window of time? (So relative instead of absolute.)
Thanks,
Jon (2 Replies)
Dear Guru's
I've a requirment to grep for a string in series of log files that are getting generated almost every minute.
I'm looking to schedule a script every 15 mountes,in order to check if the error string has been generated in any of the log files generated in last 15 minutes.
Please... (3 Replies)
RHEL 5.8
In the directory /u03/pkms/app_logs I have several hundreds of log files as shown below.
$ pwd
/u03/pkms/app_logs
$ ls -alrt *.log | tail -50
-rw-r----- 1 oracle dba 9439232 May 4 13:57 mvtpcem_1_722892404_94157.log
-rw-r----- 1 oracle dba 9227264 May 4 13:57... (8 Replies)
Hi All,
Below script will make a copy of the existing log file with the then timestamp details.
I am looking to create a copy of the existing log file for every 60 minutes and when the file limit reaches to 5, the 6th copy should overwrite the first backedup file which means all the time it... (3 Replies)
I have below command, which i use for checking last two hours log file, but i want to check 30 minutes log and discard old log, only match current time with last 30 minutes. Command i am using. This below attach log file format is for this week, but sometime it got change in time of log, so i need... (6 Replies)
OS : Red Hat Linux 6.4
Shell : Bash
We have a file called status.txt which will have only 1 line. The content will be the string "Processing" for most of the day.
# cat status.txt
Processing
#I want to write a shell script (notify.sh) which will be executing a grep every 10 minutes .
... (7 Replies)
Hi, please help with below time conversion to minutes.
one column values:
2 minutes 16 seconds 420 msec
43 seconds 750 msec
0 days 3 hours 29 minutes 58 seconds 480 msec
11 seconds 150 msec
I need output in minutes(total elapsed time in minutes) (2 Replies)
Hi all,
System Ubuntu 16.04.3 LTS
i have the following log
INFO 2019-02-07 15:13:31,099 module.py:700] default: "POST /join/8550614e-3e94-4fa5-9ab2-135eefa69c1b HTTP/1.0" 500 2042
INFO 2019-02-07 15:13:31,569 module.py:700] default: "POST /join/6cb9c452-dcb1-45f3-bcca-e33f5d450105... (15 Replies)
Discussion started by: charli1
15 Replies
LEARN ABOUT DEBIAN
shtool-arx
SHTOOL-ARX.TMP(1) GNU Portable Shell Tool SHTOOL-ARX.TMP(1)NAME
shtool-arx - GNU shtool ar(1) extensional command
SYNOPSIS
shtool arx [-t|--trace] [-C|--command cmd] op archive file [file ...]
DESCRIPTION
shtool arx is a wrapper around the archiving tool ar(1). It provides the ability to create archives out of existing archives, i.e., if one
of file matches ""*.a"", the archive member files of file are used instead of file itself.
The trick of this command is the automatic handling of archive members which is especially interesting if one wants to construct a (usually
top-level) library archive out of pre-built sub-library archives (usually staying inside subdirs) in a large source tree. For GNU libtool
based projects, a similar functionality is provided by GNU libtool internally, too.
OPTIONS
The following command line options are available.
-t, --trace
Shows the actually involved shell commands.
-C, --command cmd
Set the used ar(1) command to cmd instead of just "ar" (searched in $PATH).
EXAMPLE
# Makefile
AR=ar
RANLIB=ranlib
:
OBJS=foo.o bar.o
LIBS=baz/libbaz.a quux/libquux.a
:
libfoo.a: $(OBJS) $(LIBS)
shtool arx -C $(AR) rc libfoo.a $(OBJS) $(LIBS)
$(RANLIB) libfoo.a
HISTORY
The GNU shtool arx command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1999 for GNU shtool. It was prompted by
need to build libraries out of sub-libraries inside the OSSP project.
SEE ALSO shtool(1), ar(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-ARX.TMP(1)