I need to know if anyone can assist me on how to grab the last (we'll just say "x" minutes) of a log file. How do you tell the grep command without specifying an exact window of time? (So relative instead of absolute.)
Thanks,
Jon (2 Replies)
Dear Guru's
I've a requirment to grep for a string in series of log files that are getting generated almost every minute.
I'm looking to schedule a script every 15 mountes,in order to check if the error string has been generated in any of the log files generated in last 15 minutes.
Please... (3 Replies)
RHEL 5.8
In the directory /u03/pkms/app_logs I have several hundreds of log files as shown below.
$ pwd
/u03/pkms/app_logs
$ ls -alrt *.log | tail -50
-rw-r----- 1 oracle dba 9439232 May 4 13:57 mvtpcem_1_722892404_94157.log
-rw-r----- 1 oracle dba 9227264 May 4 13:57... (8 Replies)
Hi All,
Below script will make a copy of the existing log file with the then timestamp details.
I am looking to create a copy of the existing log file for every 60 minutes and when the file limit reaches to 5, the 6th copy should overwrite the first backedup file which means all the time it... (3 Replies)
I have below command, which i use for checking last two hours log file, but i want to check 30 minutes log and discard old log, only match current time with last 30 minutes. Command i am using. This below attach log file format is for this week, but sometime it got change in time of log, so i need... (6 Replies)
OS : Red Hat Linux 6.4
Shell : Bash
We have a file called status.txt which will have only 1 line. The content will be the string "Processing" for most of the day.
# cat status.txt
Processing
#I want to write a shell script (notify.sh) which will be executing a grep every 10 minutes .
... (7 Replies)
Hi, please help with below time conversion to minutes.
one column values:
2 minutes 16 seconds 420 msec
43 seconds 750 msec
0 days 3 hours 29 minutes 58 seconds 480 msec
11 seconds 150 msec
I need output in minutes(total elapsed time in minutes) (2 Replies)
Hi all,
System Ubuntu 16.04.3 LTS
i have the following log
INFO 2019-02-07 15:13:31,099 module.py:700] default: "POST /join/8550614e-3e94-4fa5-9ab2-135eefa69c1b HTTP/1.0" 500 2042
INFO 2019-02-07 15:13:31,569 module.py:700] default: "POST /join/6cb9c452-dcb1-45f3-bcca-e33f5d450105... (15 Replies)
Discussion started by: charli1
15 Replies
LEARN ABOUT OSX
sa1
sa1(8) BSD System Manager's Manual sa1(8)NAME
sa1 -- Generate a system activity daily data file.
SYNOPSIS
/usr/lib/sa/sa1 [t n]
DESCRIPTION
The sa1 command is a shell script used to invoke the system activity data collector, sadc. The binary sample data is collected at intervals
t seconds apart, in a loop n times. The binary sample data is written to the standard daily data file, /var/log/sa/sadd where the dd repre-
sents the current day of the month.
sa1 is intended to be started by cron.
EXAMPLE CRON ENTRY
# Starting at 8am collect system activity records
# every 20 minutes for 12 hours
# 20 minutes = 1200 seconds
# 12 hours with 3 samples each hour = 36 loops
0 8 * * 1-5 /usr/lib/sa/sa1 1200 36
# After the 12 hour period,
# collect a system activity report
30 20 * * 1-5 /usr/lib/sa/sa2 -A
FILES
/var/log/sa/sadd Default daily activity file that holds the binary sampling data. dd are digits that represent the day of the month.
SEE ALSO crontab(1), fs_usage(1), netstat(1), sar(1), sc_usage(1), top(1), vm_stat(1), crontab(5), iostat(8), sa2(8), sadc(8)Mac OS X Jul 25 2003 Mac OS X