Everyday I have to get a list of files in a directory with a special condition and feed this list to a for loop to be processed. Since I do not use Unix all the time, it is tricky for me to get that list of files. So, the question is whether there are commands that will give me the file names with a specific condition. See explanation and example below.
This is what I have to do.
Do ls -l to show all the files
Look for the last file that has a .x at the end
Get all the file names after the last .x files
Type in for x in and then copy-paste each file name separated by a space after the word in
Here is an example:
Type in ls -l and get the following list of files
Code:
A1.b.x
A2.d.e.f
A3.g.h.i
A4.j.x
A5.k.l.m
A6.n.o.p
The last file with a .x suffix is A4.j.x
So, the files after the last .x file are:
Code:
A5.k.l.m
A6.n.o.p
The for loop command will look like the following. I have to manually copy-paste the file names in.
for x in A5.k.l.m A6.n.o.p Is there a way to get the file name list with a command and then feed/pipe it to the for command?
I apologize if this is not clear. Please let me know if more clarification is needed.
Thank you.
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Please use CODE tags as required by forum rules!
Last edited by RudiC; 06-29-2018 at 01:07 PM..
Reason: Added CODE tags, removed all kinds of formatting.
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06-29-2018
