How can I apply 'date' command to specific columns, in a BASH script?
Hi everyone,
I have a situation in which I have multiple (3 at last count) date columns in a CSV file (, delim), which need to be changed from:
January 1 2017 (note, no comma after day)
to:
YYYY-MM-DD
So far, I am able to convert a date using: date --date="January 12, 1990" +%Y-%m-%d
However, I need to read a specific column in the CSV, then replace what's there with the new format. It doesn't matter which commonly used GNU utility I use, I just need to do it.
So far, I have been trying to write an AWK function in a BASH shell script to do it, but I'm completely lost.
Can anyone offer suggestions on the easiest way to accomplish this from within a BASH script? The attached sample.txt gives an idea of what the data looks like, only greatly reduced. The really data has about 3000 rows and 35 columns.
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I want to read some specific rows & columns in the .xls file with my script to get the data to be manipulated. Now, I can read the .xls file correctly & i can go to the specific sheet that I want but i have a problem to specify the specific rows & columns. I mean, I want to get the info... (0 Replies)
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PRINT0089-88615 data1 3072 Mon Dec 19 17:53:49 WITA 2011
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I have below perl script which writes xml from .xls file.
Now i want to add below two conditions in this script :
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Hi All
I have a file which has five columns in each rows.
cat file.txt
a|b|c|d|e
1|2|3|4|5
a1|a2|a3|a4|a5
.
.
.
I need to make sure that there are no less than five or more than five columns (in all the rows) by mistake. I tried this :
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Hello,
I have a requirement to apply hashing algorithm on flat file on one or more columns dynamically based on header
sample input file
ID|NAME|AGE|GENDER
10|ABC|30|M
20|DEF|20|F
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