Find and replace the path value in files, pattern is not full known.
Hi,
I need to do find and replace, but the pattern is not full known.
for example,
my file has /proj/app-d1/sun or /data/site-d1/conf
here app-d1 and site-d1 is not constant. It may be different in different files. common part is /proj/xx/sun and /data/xxx/conf
i want to find where ever /proj/xxx/sun or /data/xxx/conf present and replace it with the path value i desire which i have constant values. please suggest how to do this.
Below is the one line which has the patterns to find, i want to replace it with differnt path. here cesite1-d1 is not constant, it may be different in other files.
Moderator's Comments:
Please use CODE tags as required by forum rules!
Last edited by RudiC; 06-04-2018 at 03:49 PM..
Reason: Added CODE tags.
Hi
How can I looking for a pattern found in more than one file and replace it with anther pattern
this what I was used:
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Hi,
I have written this shell script:
fl=`ls -1lrt $mylist | grep '\.xml$' | awk '{print $9}'`
echo $fl (1)
for i in $fl
do
for dir in $mylist
do
if
then
echo $dir/$i >> tmp (2)
fi
done
done
The mylist contains some directory names. The satement (1) gives the sorted list... (5 Replies)
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original file..
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Hi all,
How to save file full name to a file. I tried the following but don't know to include path name.
$ ls -l | awk '{print $9}' > outputfile.dat
$ cat outputfile.dat
fifth.txt
first.txt
fourth.txt
second.txt
third.txt
My wanted result is ie:
... (3 Replies)
Hi,
I need to store all the files in a directory to a text file with its full path.
The example below can explain:
./File1.txt
./File2.txt
./Folder1/File11.txt
./Folder1/File12.txt
./Folder1/Folder11/File111.txt
./Folder2/file21.txt
:
:
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I want to pattern match only path part from below and replace them with new path string.
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Hello.
Question 1 :
I want to comment out all lines of a cron file which are not already commented out for each full path pattern matched.
Example 1 nothing to do because line is already commented out; pattern = '/usr/bin/munin-cron'
# */5 * * * * munin test -x... (3 Replies)
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output:
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Discussion started by: Rajesh123
5 Replies
LEARN ABOUT DEBIAN
nad2bin
NAD2BIN(1) General Commands Manual NAD2BIN(1)NAME
nad2bin - convert nad ASCII files into binary format usable by nad2nad
DESCRIPTION
This command is undocumented upstream. This very rough documentation was quickly assembled by your friendly Debian maintainer (who doesn't
use this command, and so is not the best person to document it!).
The proj package includes the nad2nad binary, the North American Datum conversion filter used to convert data between North America Datum
1927 (NAD27) and North American Datum 1983, and cs2cs a binary that performs transformation between the source and destination cartographic
coordinate system on a set of input points. The coordinate system transformation can include translation between projected and geographic
coordinates as well as the application of datum shifts.
See the nad2nad(1) and cs2cs(1) man pages for more information.
nad2nad and cs2cs need arch-dependent conversion data files in a library directory, /usr/share/proj/ Those files are included in the proj
Debian package since 4.6.1-5. To produce/update them yourself, get the *.lla files from
http://download.osgeo.org/proj/proj-datumgrid-1.5.zip
and then run nad2bin to produce the binary files used by nad2nad and cs2cs like so:
# nad2bin < conus.lla /usr/share/proj/conus
Test nad2nad with the following example:
$ nad2nad -i 83 -o 27 -r conus << EOF
71d14'58.27"W 44d20'15.227"N
EOF
It should produce:
71d15'W 44d20'15"N
SEE ALSO nad2nad(1), cs2cs(1)AUTHOR
This manual page by Peter S Galbraith <psg@debian.org>.
NAD2BIN(1)