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Top Forums UNIX for Beginners Questions & Answers Fetching address and user details from log file Post 303018113 by RudiC on Tuesday 29th of May 2018 10:03:56 AM
Old 05-29-2018
Try

Code:
gunzip log.2018-05-23.gz | awk '
BEGIN                           {HD = "Date    Program    line1    line2    city    stateCode    postalCode    countryCode"
                                 MX = split(HD, HDFLDS)
                                }

/CartService/                   {TMP = $1 " " $2 OFS $5
                                }

/Failed to calculate US Tax.*{/ {while (!(T1 ~ /}/))    {getline T1
                                                         gsub (/ *" */, _, T1)
                                                         split (T1, T2, ":")
                                                         OUT[T2[1]] = T2[2]
                                                        }

                                 if (!HDprinted) print HD
                                 HDprinted = 1

                                 printf "%s", TMP
                                 for (i=3; i<=MX; i++) printf OFS "%s", OUT[HDFLDS[i]]
                                  printf ORS


                                 TMP = T1 = ""
                                 split ("", OUT)
                                }

 ' OFS="\t"

 

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SHTOOL-PATH.TMP(1)					      GNU Portable Shell Tool						SHTOOL-PATH.TMP(1)

NAME
shtool-path - GNU shtool command dealing with shell path variables SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...] DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found. OPTIONS
The following command line options are available. -s, --suppress Supress output. Useful to only test whether a program exists with the help of the return code. -r, --reverse Transform a forward path to a subdirectory into a reverse path. -d, --dirname Output the directory name of str. -b, --basename Output the base name of str. -m, --magic Enable advanced magic search for ""perl"" and ""cpp"". -p, --path path Search in path. Default is to search in $PATH. EXAMPLE
# shell script awk=`shtool path -p "${PATH}:." gawk nawk awk` perl=`shtool path -m perl` cpp=`shtool path -m cpp` revpath=`shtool path -r path/to/subdir` HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken over into GNU shtool. SEE ALSO
shtool(1), which(1). 18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)
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