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Top Forums Shell Programming and Scripting Subprocess.popen() should write to log without waiting for process to complete Post 303018087 by ezee on Tuesday 29th of May 2018 01:49:22 AM
Old 05-29-2018
I got working solution
Code:
with sp.Popen(['make', '-C'] + [os.path.expandvars(item) for item in
                                            make_line],
                          bufsize=0,
                          stdout=sp.PIPE, stderr=sp.STDOUT,
                          cwd=src_home) as process:
                for line in process.stdout:
                    print(line.decode('utf-8').strip())

This User Gave Thanks to ezee For This Post:
 

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OMPI-IOF(1)							     Open MPI							       OMPI-IOF(1)

NAME
ompi-iof, orte-iof - Displays a copy of the output streams from a process. NOTE: ompi-iof, and orte-iof are exact synonyms for each other. Using any of the names will result in exactly identical behavior. SYNOPSIS
ompi-iof [ options ] Options ompi-iof will display a copy of the indicated stdout, stderr, and/or stddiag streams from the designated process. -pid | --pid The pid of the mpirun executing the process whose streams are to be copied -stdout | --stdout Display a copy of the specified process' stdout. If no options are specified, this will act as the default -stderr | --stderr Display a copy of the specified process' stderr. -stddiag | --stddiag Display a copy of the specified process' stddiag. -rank | --rank The rank of the process whose output is to be copied. DESCRIPTION
ompi-iof displays a copy of the indicated stdout, stderr, and/or stddiag streams from the designated process. At this time, a ctrl-C must be used to terminate the program. The program will terminate cleanly, telling the associated mpirun to close the requested streams before exiting. SEE ALSO
orterun(1) 1.4.5 Feb 10, 2012 OMPI-IOF(1)
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