I have no idea what you are trying to do but your function is not called.
I guess you are trying to put that function in the interpreter namespace for other uses.
The function has a useless line and looks as though you want Python version 2.x.x and the print STATEMENT.
If you require version 3.x.x then you need the print FUNCTION and the end=" " _flag_.
OSX 10.13.4, default bash terminal calling python2.7.
Last edited by wisecracker; 05-27-2018 at 06:57 AM..
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LEARN ABOUT DEBIAN
lp-shell
lp-shell(1) General Commands Manual lp-shell(1)NAME
lp-shell - Open an interactive launchpadlib shell.
SYNOPSIS
lp-shell [-a] [-cPROGRAM] [--python] [--ipython] [service] [LP API version]
DESCRIPTION
lp-shell opens an interactive Python shell with a launchpadlib.Launchpad object "lp" which is ready for use.
It authenticates against Launchpad with the consumer name "udt-lp-shell". When using lp-shell with the -a option it will use the anonymous
login from launchpadlib.Launchpad.
By default lp-shell connects to the "production" Launchpad service using the "1.0" LP API version.
If you want to connect to another Launchpad service, call lp-shell with the service name as the second argument. lp-shell supports all ser-
vices known by launchpadlib Python module. Currently known are (list can be incomplete or outdated): "production", "staging", "dogfood".
A different LP API version can be selected by passing the API version to use as the third argument. Current supported are: "beta", "1.0"
and "devel".
OPTIONS -a Login anonymously into Launchpad.
-c PROGRAM
Don't enter a shell but only run the specified Python program and exit.
--ipython
Use an ipython shell if available (default).
--python
Use a regular python shell.
AUTHORS
lp-shell was written by Martin Pitt <martin.pitt@ubuntu.com>.
It is released under the terms of the GNU General Public License, version 2 or (at your option) any later version.
lptools 27 March 2010 lp-shell(1)